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katovenus [111]

3 years ago

7

A certain quantity decays exponentially over time. The initial quantity at t = 0 is 1,000. The quantity decays at a rate of 2%.

What is the quantity at t = 4?

2 answers:

PtichkaEL [24]3 years ago

6 0

A=1000(1-0.02)^4
A==922.37

n200080 [17]3 years ago

4 0

Its D according to edgenuity.

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X= r-h/y<br> solve for h and r

malfutka [58]

X = r - h/y ; Solve for h & r

Let's first solve for h :)

Add h/y to both sides.

h/y + x = r

So, r = h/y + x

Now, let's solve for h.

x = r-h/y

Subtract r from both sides.

-r + x = -h/y

Multiply both sides by y.

y(-r + x) = y(-h/y)

Simplify.

-ry + xy = -h

Divide both sides by -1.

ry - xy = h

So, h = ry - xy

~Hope I helped!~

3 0

2 years ago

Read 2 more answers

Catriona spotted a major problem having to do with patient billing. A number of people may have received the wrong bills. When s

Olenka [21]

Answer:

C

Step-by-step explanation:

When she first noticed the problem

3 0

2 years ago

Vanessa wants to purchase a new cell phone plan. The two plans from which she can choose are shown below. Vanessa used the syste

user100 [1]

Answer:

2. 325 minutes.

Step by step explanation:

We will substitute our given number of minutes in our both equation one by one to find the correct option.

1. Let us substitute m= 775 in both equations.

$CA=22+0.13m$

$CA=22+0.13\cdot 775$

$CA=22+100.75=122.75$

$CB=44+0.09(m-100)$

$CB=44+0.09(775-100)$

$CB=44+0.09\cdot675$

$CB=44+60.75=104.75$

$104.75\neq122.75$

We can see that both plans have different costs , therefore, 1st option is incorrect.

2. Let us substitute m= 325 in both equations.

$CA=22+0.13m$

$CA=22+0.13\cdot 325$

$CA=22+42.25=64.25$

$CB=44+0.09(m-100)$

$CB=44+0.09(325-100)$

$CB=44+0.09\cdot 225$

$CB=44+20.25=64.25$

$64.25=64.25$

When Vanessa has used the phone for 325 minutes, the cost for Plan A and the cost for Plan B will both be $64.25.Therefore, 2nd option is correct choice.

3. Let us substitute m= 32.5 in both equations.

$CA=22+0.13m$

$CA=22+0.13\cdot 32.5$

$CA=22+4.225=26.225$

$CB=44+0.09(m-100)$

$CB=44+0.09(32.5-100)$

$CB=44+0.09\cdot -67.5$

$CB=44-6.075=37.925$

$37.925\neq26.225$

4. Let us substitute m= 764 in both equations.

$CA=22+0.13m$

$CA=22+0.13\cdot 764$

$CA=22+99.32=121.32$

$CB=44+0.09(m-100)$

$CB=44+0.09(764-100)$

$CB=44+0.09\cdot 664$

$CB=44+59.76=103.76$

$121.32\neq103.76$

Therefore, 4th option is incorrect.

3 0

3 years ago

PLEASE! Help me with the third one. I am totally lost. I appreciate any help. If you can't see the picture let me know

vazorg [7]

I can only tell u the formula
a²+b²=c²

3 0

3 years ago

One light-year equals 5.9 x 1012 miles. How many light-years are in 6.79

inna [77]

Option B

The number of light years in $6.79 \times 10^{16}$ miles is 11508 light years

<em><u>Solution:</u></em>

Given that,

One light-year equals 5.9 x 10^12 miles

Therefore,

$1 \text{ light year } = 5.9 \times 10^{12} \text{ miles }$

To find: Number of light years in $6.79 \times 10^{16}$ miles

Let "x" be the number of light years in $6.79 \times 10^{16}$ miles

Then number of light years in $6.79 \times 10^{16}$ miles can be found by dividing $6.79 \times 10^{16}$ miles by miles in 1 light year

$\text{Number of light years in } 6.79 \times 10^{16} miles = \frac{6.79 \times 10^{16}}{5.9 \times 10^{12}}\\\\\text{Use the law of exponent }\\\\\frac{a^m}{a^n} = a^{m-n}\\\\\text{Number of light years in } 6.79 \times 10^{16} miles = \frac{6.79}{5.9} \times 10^{16-12}\\\\\text{Number of light years in } 6.79 \times 10^{16} miles = 1.1508 \times 10^4\\\\\text{Number of light years in } 6.79 \times 10^{16} miles = 11508$

Thus number of light years in $6.79 \times 10^{16}$ miles is 11508 light years

3 0

3 years ago