Answer:
Step-by-step explanation:
0: -2
1: -4
2: -6
We are given: On january 1, 2000 initial population = 67,255.
Number of people increase each year = 2935 people.
Therefore, 67,255 would be fix value and 2935 is the rate at which population increase.
Let us assume there would be t number of years after year 2000 and population P after t years is taken by function P(t).
So, we can setup an equation as
Total population after t years = Number of t years * rate of increase of population + fix given population.
In terms of function it can be written as
P(t) = t * 2935 + 67255.
Therefore, final function would be
P(t) = 2935t +67255.
So, the correct option is d.P(t) = 67255 + 2935t.
the sequence is in multiples of 4 (2*4=8, 8*4=32, 32*4=128)
so 128*4=512, 512*4=2048, 2048*4=8192 & 8192*4=32768
2+8+32+128+512+2048+8192+32768=43690
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just add the 2 numbers together,
the less expensive player cost $238 and it is $98 less than the more expensive one
more expensive one cost 238 + 98 = $336
