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2 years ago

9

Correlation coefficients indicate the: internal and external validity between variables. magnitude and direction of the relation

ship between variables. significance and variability between variables. cause-and-effect relationship between variable

1 answer:

Nutka1998 [239]2 years ago

6 0

Answer:

n

Explanation:

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The boiling point of sulfur is 444.6 celsius .sulfur melting point is 586.1 fahrenheit lower than its boiling?

rewona [7]

Answer:

(a) Melting point is 136.8°C

(b) Melting point is 278.24°F

Boiling point is 832.28°F

(c) Melting point is 409.8K

Boiling point is 717.6K

Explanation:

(a) 586.1°F = 5/9(586.1 - 32)°C = 307.8°C

Melting point = 444.6°C - 307.8°C = 136.8°C

(b) Melting point = 136.8°C = (9/5×136.8) + 32 = 278.24°F

Boiling point = 444.6°C = (9/5×444.6) + 32 = 832.28°F

(c) Melting point = 136.8°C = 136.8 + 273 = 409.8K

Boiling point = 444.6°C = 444.6 + 273 = 717.6K

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3 years ago

a tire rolls from rest to an angular velocity of 6 radians per second. the angle it turns through is 12 radians. what is the ang

True [87]

Answer:

$\alpha =1.5\ rad/s^2$

Explanation:

Given that,

Initial angular velocity, $\omega_i=0$

Final angular speed, $\omega_f=6\ rad/s$

Angular displacement, $\theta=12\ rad$

We need to find the angular acceleration of the tire. We can find it using the third equation of rotational kinematics. So,

$\omega_f^2-\omega_i^2=2\alpha \theta\\\\\alpha =\dfrac{\omega_f^2-\omega_i^2}{2\theta}\\\\\alpha =\dfrac{6^2-0^2}{2\times 12}\\\\\alpha =1.5\ rad/s^2$

So, the angular acceleration of the tire is equal to $1.5\ rad/s^2$ .

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3 years ago

Steam machines are used to sterilise kitchen work surfaces.

algol [13]

Answer:

Styleusso customer care number 8388026087//8388026087 refund ke liye call kare

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3 years ago

A box is against a wall. A person pushes on the box, but the box does not move. Is this situation an example of a force

Leya [2.2K]

Answer: I don’t think so, because the box is ALREADY against the wall so you can’t move it further into the wall

Explanation:

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3 years ago

Read 2 more answers

A ball is thrown upward. At a height of 10 meters above the ground, the ball has a potential energy of 50 Joules (with the poten

Brilliant_brown [7]

Given that,

A ball is thrown upward. At a height of 10 meters above the ground, the ball has a potential energy of 50 Joules. It is moving upward with a kinetic energy of 50 Joules.

We need to find the maximum height h reached by the ball. Let at a height of 10 meters, it has a potential energy of 50 Joules. So,

$mgH=50\\\\mg=\dfrac{50}{h}\\\\mg=\dfrac{50}{10}\\\\mg=5\ N$ ........(1)

Let at a height of h m, it reaches to a maximum height. at this point, it has a total of 100 J of energy. So,

$mgh=50+50\\\\mgh=100\\\\h=\dfrac{100}{5}\\\\h=20\ m$

So, the correct option is (E) "h = 20 m".

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3 years ago