First, we must find the vertical distance traveled upwards by the ball due to the throw. For this, we will use the formula:
2as = v² - u²
Because the final velocity v is 0 in such cases
s = -u²/2a; because both u and a are downwards, the negative sign cancels
s = 14.5² / 2*9.81
s = 10.72 meters
Next, to find the time taken to reach the ground, we need the height above the ground. This is:
45 + 10.72 = 55.72 m
We will use the formula
s = ut + 0.5at²
to find the time taken with the initial velocity u = 0.
55.72 = 0.5 * 9.81 * t²
t = 3.37 seconds
Answer:
I believe the answer for this question is D
Explanation:
I hope this helps and is correct
Answer:
255 [m].
Explanation:
1) the formula is (d - requred distance, V₀ - initial velocity, t - elapsed time, a - deceleration):
2) according to the formula above the required distance is:
d=10*30-0.5*0.1*900=300-45=255 [m].