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Artemon [7]
2 years ago
7

I need help with 7 and 9. It is almost due!!

Mathematics
1 answer:
otez555 [7]2 years ago
6 0
The answer to question seven and question nine is
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Verdadero o falso a) al reducir a comun denominador las fracciones se sustituyen por otras equivalentes
alexgriva [62]

Answer:

Verdadero

Step-by-step explanation:

Verdadero, cuando cambias dos fracciones para darles un denominador comun la fraccion entera se sustituye para otra que tiene el mismo valor numerico que la original. Por ejemplo tenemos una fraccion 2/6 en la cual tenemos que cambiarle el denominador a uno comun con otra fraccion que es 18. Entonces sustituyemos la fraccion por la siguente fraccion 6/18. Esta nueva fraccion es equivalente a la original y los dos tienen el mismo valor numerico...

2 / 6 = 0.333

6 / 18 = 0.333

3 0
3 years ago
How many
Alenkinab [10]

Answer:

1444

Step-by-step explanation:

multiply

3 0
3 years ago
Read 2 more answers
Help me ;-; its due today
antiseptic1488 [7]

Answer:

Question? It's incomplete.

5 0
3 years ago
Read 2 more answers
Visitors to a carnival can buy an unlimited-ride pass for $50 or an entrance-only pass for $20. In one day, 282 passes were sold
baherus [9]

Answer:

The  unlimited-ride passes sold are equal to 168

Step-by-step explanation:

According to given scenario:

x = unlimited-ride passes

y = entrance-only pass

Given that:

50x + 20y = 10,680  -------- eq1

x + y = 282  ------------ eq2

From eq2:

x = 282 - y

Putting value of x  in eq1:

50(282 - y) + 20y = 10,680

By simplifying:

14,100 - 50y + 20y = 10,680

14,100 - 30y = 10,680

30y = 14,100 - 10680

30y = 3,480

Dividing both sides by 30

y = 114

Now put value of y in eq2:

x + 114 = 282

x = 282 - 144

x = 168

So, the  unlimited-ride passes sold are equal to 168

i hope it will help you!

6 0
4 years ago
Read 2 more answers
Simplify completely
olasank [31]

Answer: D

<u>Step-by-step explanation:</u>

\frac{x^{2}-15x+56} {x-7}

First, factor the numerator (top):

x² - 15x + 56

                ∧

              -1   -56

              -2  -28

              -4   -14

              -7    -8  = -15

        (x - 7)(x - 8)

Next, cancel out like terms from the numerator and denominator:

\frac{(x-7)(x-8)} {x-7} = x - 8



5 0
3 years ago
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