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2 years ago

What is 57.82 ÷ 0.784 (show ur work)

Mathematics

1 answer:

faltersainse [42]2 years ago

8 0

Answer:

73.75

Step-by-step explanation:

$\frac{57.82}{0.784}$
Multiply numerator and denominator by 1000:

$\frac{57820}{784}$

Divide 57820 by 784 to get 7
Now divide 2940 by 784 to get 3

Now divide 5880 by 784 to get 7

Now divide 3920 by 784 to get 5

The solution of the long division is :

73.75

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Chris wanted to transform the graph of the parent function Y= cot (x) by horizontally compressing it so that it has a period of

pashok25 [27]

Answer:

He didn't calculate the b-value correctly.

Step-by-step explanation:

The given parent function is:

$y = \cot(x)$

The transformation is of the form:

$y =a \cot(bx + c) + d$

The period is given by

$\frac{\pi}{b}$

If we want the new function to have a period of

$\frac{2}{\pi}$

Then we solve the following equation for b.

$\frac{\pi}{b} = \frac{2}{\pi}$

$b = \frac{ {\pi}^{2} }{2}$

$- \frac{c}{b}$

will translate the graph horizontally to the right by

$\frac{c}{b}$

units.

+d shifts the graph up by d units.

The new function then becomes:

$y = \cot( \frac{ {\pi}^{2} }{2} (x - \frac{\pi}{4} ) )+1$

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3 years ago

Read 2 more answers

Which of the equation is graphed below

Darina [25.2K]

A, because 1/4 is your slope of the line. which means you find a point where the line intersects and count 1 up and four over to the right and should end up where the line touches the graph again. if it were to be -1/4 it would be opposite and the line would be going the other way. and 1 would be your y-intercept. this is where the line crosses over the y axis at 1! hope you found this helpful!

8 0

3 years ago

leah won 37 super bouncy balls playing hoops at her school's game night. Later,she gave two to each of her friends.She only has

givi [52]

37 - 7 = 30

30 : 2 = 15 friends

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3 years ago

.. Which of the following are the coordinates of the vertices of the following square with sides of length a?

atroni [7]

Option A: $O(0,0), S(0,a), T(a,a), W(a,0)$

Option D: $O(0,0), S(a,0), T(a,a), W(0,a)$

Step-by-step explanation:

Option A: $O(0,0), S(0,a), T(a,a), W(a,0)$

To find the sides of a square, let us use the distance formula,

$d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Now, we shall find the length of the square,

$\begin{array}{l}{\text { Length } O S=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } S T=\sqrt{(a-0)^{2}+(a-a)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } T W=\sqrt{(a-a)^{2}+(0-a)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } O W=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a}\end{array}$

Thus, the square with vertices $O(0,0), S(0,a), T(a,a), W(a,0)$ has sides of length a.

Option B: $O(0,0), S(0,a), T(2a,2a), W(a,0)$

Now, we shall find the length of the square,

$\begin{aligned}&\text { Length } O S=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\\&\text {Length } S T=\sqrt{(2 a-0)^{2}+(2 a-a)^{2}}=\sqrt{5 a^{2}}=a \sqrt{5}\\&\text {Length } T W=\sqrt{(a-2 a)^{2}+(0-2 a)^{2}}=\sqrt{2 a^{2}}=a \sqrt{2}\\&\text {Length } O W=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a\end{aligned}$

This is not a square because the lengths are not equal.

Option C: $O(0,0), S(0,2a), T(2a,2a), W(2a,0)$

Now, we shall find the length of the square,

$\begin{array}{l}{\text { Length OS }=\sqrt{(0-0)^{2}+(2 a-0)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } S T=\sqrt{(2 a-0)^{2}+(2 a-2 a)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } T W=\sqrt{(2 a-2 a)^{2}+(0-2 a)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } O W=\sqrt{(2 a-0)^{2}+(0-0)^{2}}=\sqrt{4 a^{2}}=2 a}\end{array}$

Thus, the square with vertices $O(0,0), S(0,2a), T(2a,2a), W(2a,0)$ has sides of length 2a.

Option D: $O(0,0), S(a,0), T(a,a), W(0,a)$

Now, we shall find the length of the square,

$\begin{aligned}&\text { Length OS }=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } S T=\sqrt{(a-a)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } T W=\sqrt{(0-a)^{2}+(a-a)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } O W=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\end{aligned}$

Thus, the square with vertices $O(0,0), S(a,0), T(a,a), W(0,a)$ has sides of length a.

Thus, the correct answers are option a and option d.

8 0

3 years ago

What is the product? (2x-1)(x+4) O 2x2-4 O 2x2+4 O 2x2 +7x-4 O 2x2-7x-4

Alona [7]

Answer:

2x2+7x-4

Step-by-step explanation:

2x2+8x-x-4

2x2+7x-4

7 0

3 years ago