Find the value of C that makes the trinomial a perfect square HELP PLS SHOW WORK 30 POINTS

Mathematics

1 answer:

lesya692 [45]2 years ago

4 0

Answer:

$\frac{9}{4}$

Step-by-step explanation:

${(x + \frac{3}{2} )}^{2} = {x}^{2} + 3x + \frac{9}{4}$

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(1) Solve this system using the substitution method: y = 2x – 3; y = (1/2)x - 4

Darya [45]

Answer:

X=2

Step-by-step explanation:

y= 2x- 3

1/2x= 2x-3

1/2x-2x= -3

x-4x= 2*-3

-3x=-6

x=2

8 0

3 years ago

Let f(x) = 2x2 − 9x and g(x) = -5x2 + 4x. Find f(x) − g(x).

Paha777 [63]

F(x) − g(x) = 2x^2 − 9x - (<span> -5x^2 + 4x)
</span>f(x) − g(x) = 2x^2 − 9x + 5x^2 - 4x
f(x) − g(x) = 7x^2 - 13x

8 0

4 years ago

What are the solutions of x^2 = -7x-8

Vilka [71]

$Solution, solve\:for\:x,\:x^2=-7x-8\quad :\quad x=\frac{-7+\sqrt{17}}{2},\:x=\frac{-7-\sqrt{17}}{2}$

$Steps:$

$x^2=-7x-8$

$\mathrm{Add\:}8\mathrm{\:to\:both\:sides},\\x^2+8=-7x-8+8$

$\mathrm{Simplify},\\x^2+8=-7x$

$\mathrm{Add\:}7x\mathrm{\:to\:both\:sides},\\x^2+8+7x=-7x+7x$

$\mathrm{Simplify},\\x^2+7x+8=0$

$Solve\:with\:the\:quadratic\:formula,\\\mathrm{For\:}\quad a=1,\:b=7,\:c=8:\quad x_{1,\:2}=\frac{-7\pm \sqrt{7^2-4\cdot \:1\cdot \:8}}{2\cdot \:1},\\x=\frac{-7+\sqrt{7^2-4\cdot \:1\cdot \:8}}{2\cdot \:1}:\quad \frac{-7+\sqrt{17}}{2},\\x=\frac{-7-\sqrt{7^2-4\cdot \:1\cdot \:8}}{2\cdot \:1}:\quad \frac{-7-\sqrt{17}}{2}$