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andrezito [222]
2 years ago
11

Solve for C⁰... photo above​

Mathematics
1 answer:
Sati [7]2 years ago
5 0

Answer:

c = 9

Step-by-step explanation:

Since angle d and 59 are on a right angle (indicated by the small square)

We can equate the sum of these angles to 90:

d+59=90

Now we subtract 59 from both sides:

d+59-59=90-59

d=31

Since angles d,c and 140 are on a straight line we can equate the sum of these 3 to 180:

c+d+140=180

Substitute d with 31 from previous working out:

c+31+140=180

Simplify:

c+171=180

Subtract 171 from both sides:

c+171-171=180-171

Simplify:

c= 9

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The sum of three consecutive even numbers is 96. What is the smallest of the three numbers
lidiya [134]
The answer is 30.

First off, the numbers are consecutive even numbers. So, the difference between every consecutive number is 2 (numbers go from even to odd to even to odd...). Since the sum of their numbers is 96, I divided that by 3 to get 32. This gives me the median of the three numbers. To find the smallest number, I simply subtracted 2 from the 32.


This may help:

96/3=32

32 + 32 + 32 = 96
(32-2)+(32+0)+(32+2)=96
30+32+34=93
8 0
3 years ago
Evaluate P (5,3)<br>A.15<br>B.20<br>C.60
atroni [7]
Am i supposed to multiply? 5 times 3 equals 15 
3 0
3 years ago
Read 2 more answers
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

The above equation can be better expressed as:

y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

p(x) = \dfrac{(x+2)}{(x^2-4)^2} \

p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \

p(x) = \dfrac{1}{(x+2)(x-2)^2}

Also;

q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{1}{(x-2)^2}

\implies \dfrac{1}{16}

\lim \limits_{x \to-2} (x+ 2)^2 q(x) =  \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{7}{(x-2)^2}

\implies \dfrac{7}{16}

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0
3 years ago
Why the denator in the numerator stay the same
nika2105 [10]
Because it is like having a unit of measurement that is set
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8 0
4 years ago
What is the answer to this equation? Must solve for x.<br> x+5=12x−4
natulia [17]

Answer:

x = 9/11

Step-by-step explanation:

x + 5 = 12x - 4

Subtract x from both sides

x + 5 - x = 12x - x - 4

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Add 4 to both sides

      5+ 4 = 11x - 4 + 4

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Divide both sides by 11

         9/11 = 11x/11

          9/11 = x

x = 9/11

8 0
3 years ago
Read 2 more answers
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