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Len [333]
2 years ago
8

How do i figure this out?

Mathematics
1 answer:
julsineya [31]2 years ago
4 0

Answer:

Step-by-step explanation:

put the left hand numbers into your calculator, find the answers.

put the equations at the bottom in your calculator and figure out which is equal to which

1. fourth answer on the botton

2. first one

3. third one

4. second one

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nikdorinn [45]

Answer:We need to see the net.

Step-by-step explanation:

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3 years ago
What is the product of -2x^3+x-5 and x^3-3x-4 ?
murzikaleks [220]
To find the product of <span>-2x^3+x-5 and x^3-3x-4, we need to multiply each term in the first polynomial by the second polynomial. (So, x^3 - 3x - 4) times ....
-2x^3 = -2x^6 + 6x^4 + 8x^3
x = x^4 - 3x^2 - 4x
-5 = -5x^3 + 15x + 20
If we add all these together, we get (-2x^6 + 7x^4 + 3x^3 - 3x^2 + 11x + 20)</span>
6 0
3 years ago
Explain why a graph that fails the vertical-line test does not represent a function. Be sure to use the definition of a function
ArbitrLikvidat [17]

Explanation:

A function is a relationship where any one x-value/input only has <u>one </u>corresponding y-value/output. (note: a y-value can have multiple x-values).

> This can be called "assigning one y-value to every x element".

The vertical line test places a line that would connect all y-values of an x-value (that is, if it were to have multiple y-values). If multiple points can be found along the vertical line, it is, therefore, by the definition of a function, not a function. (Because an x-value will have more than one y-value).

So, a graph that fails the vertical-line test does not represent a function because an x-value will correspond with more than one y-value.

hope this helps!!

4 0
1 year ago
The area of a circular pool cover is 314 square feet. Write and solve an equation to find the diameter of the pool cover. Use 3.
nikitadnepr [17]
The diameter of the pool cover in one hundred feet
4 0
3 years ago
If a+b+c=0 then find the value of a^2+b^2+c^2/a^2-bc pls help me
VladimirAG [237]

a+b+c=0

[(a+b+c)^2=a^2+b^2+c^2+2ab+2ac+2bc]

[a^2+b^2+c^2+2ab+2ac+2bc=0]

[a^2+b^2+c^2=-(2ab+2ac+2bc)]

[a^2+b^2+c^2=-2(ab+ac+bc)] (i)

also

[a=-b-c]

[a^2=-ab-ac] (ii)

[-c=a+b]

[-bc=ab+b^2] (iii)

adding (ii) and (iii) ,we have

[a^2-bc=b^2-ac] (iv)

devide (i) by (iv)

[(a^2+b^2+c^2)/(a^2-bc)=(-2(ab+bc+ca))/(b^2-ac)]
8 0
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