a^4+2a+8 because if you combine like terms that is what you get
Answer:
2/6
Step-by-step explanation:
The answer is
<span>B.
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Let's find the derivative of that hyperbola in order to find a slope formula to help us with this equation. We already have an x and y value. The derivative is found this way:

so

. The derivative supplies us with the slope formula we need to write the equation. Sub in the x value of 3 to find what the slope is:

. So in our slope-intercept equation, x = 3, y = 1, and m = -1/3. Use these values to solve for b.

so b = 2. The equation, then, for the line tangent to that hyperbola at that given point is
Ok, first group x terms
f(x)=(x²+4x)-8
factor out quadratic coefient (no need but that's the step)
f(x)=1(x²+4x)-8
take 1/2 of the linear coefient and square it
4/2=2, (2)²=4
add positive and negative of it insides the parenthasees
f(x)=1(x²+4x+4-4)-8
factor perfect square
f(x)=1((x+2)²-4)-8
distribute
f(x)=1(x+2)²-4-8
f(x)=1(x+2)²-12
and, now if we wanted to find the x intercepts where f(x)=0 then
0=1(x+2)²-12
12=(x+2)²
+/-2√3=x+2
-2+/-2√3=x
x=-2+2√3 or -2-2√3
that is where the x intercept are
and completed square form is
f(x)=(x+2)²-12