First you need to work out how much string is needed -
256 pieces needed x 40cm each:
256 x 40 = 10240cm
Then, convert to metres (100cm = 1m)
10240 / 100 = 102.4m
Then, you work out how many balls are needed:
30 can fit into 102.4 3 times with .41m to spare. So, you need three balls of string, PLUS another one to cover the 41cm
So to conclude: 4 balls of string are needed.
Using the greatest common factor, it is found that the greatest dimensions each tile can have is of 3 feet.
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- The widths of the walls are of <u>27 feet, 18 feet and 30 feet.</u>
- <u>The tiles must fit the width of each wall</u>, thus, the greatest dimension they can have is the greatest common factor of 27, 18 and 30.
To find their greatest common factor, these numbers must be factored into prime factors simultaneously, that is, only being divided by numbers of which all three are divisible, thus:
27 - 18 - 30|3
9 - 6 - 10
No numbers by which all of 9, 6 and 10 are divisible, thus, gcf(27,18,30) = 3 and the greatest dimensions each tile can have is of 3 feet.
A similar problem is given at brainly.com/question/6032811
95 times 2 is 190.
90 times 2 is 180, and 5 times 2 is 10.
180 + 10 = 190.
Answer:
Sample Response: First, the like terms had to be combined using the lowest common denominator (LCD). Then the subtraction property of equality was used to isolate the variable term. Finally, both sides of the equation were multiplied by the reciprocal of the coefficient to solve for a.
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
Since cosine is positive and sine is negative that puts θ in Quad IV.
From right triangles we know:
Cos θ = adjacent/hypotenuse = 5/13
sin θ = opposite/hypotenuse = ?/13
To find the opposite side across from θ use the pythagorean theorem.
5² + y² = 13²
25 + y² = 169
y² = 144
y = 12
we are given that sin is < 0 so sinθ = -12/13
