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3 years ago

7

According to police sources, a car with a certain protection system will be recovered 86% of the time. Find the probability tha

t 5 of 6 stolen cars will be recovered
Please help

1 answer:

IRINA_888 [86]3 years ago

7 0

Answer:

0.01145

Step-by-step explanation:

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Step-by-step explanation:

I do believe it's 8

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What is (f−g)(x)<br> (f−g)(x)=

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Answer:

3x^5 -2x^4 -x^2 +x -21

Step-by-step explanation:

We need to subtract g(x) from f(x)

f(x) = 3x^5 +6x^2 -5

g(x) = 2x^4 +7x^2 -x+16

f(x) -g(x) = 3x^5 +6x^2 -5 - (2x^4 +7x^2 -x+16)

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3x^5 +6x^2 -5

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---------------------------------------

3x^5 -2x^4 -x^2 +x -21

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3 years ago

Write an integer for each situation.(In this exercise you must Wirte the + and Negative signs) 1.) A profit of $12 2.) 1,440 fee

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4-member curling team is randomly chosen from 6 grade 11 students and 8 grade 12 students. What is the probability that the team

Ivanshal [37]

Answer:

0.5944 = 59.44% probability that the team has at least 2 grade 11 students

Step-by-step explanation:

The students are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

We have that:

6 + 8 = 14 students, which means that $N = 14$

6 grade 11 students means that $k = 6$

Teams of 4 members means that $n = 4$

What is the probability that the team has at least 2 grade 11 students?

This is:

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,14,4,6) = \frac{C_{6,0}*C_{8,4}}{C_{14,4}} = 0.0699$

$P(X = 1) = h(1,14,4,6) = \frac{C_{6,1}*C_{8,3}}{C_{14,4}} = 0.3357$

Then

$P(X < 2) = P(X = 0) + P(X = 1) = 0.0699 + 0.3357 = 0.4056$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.4056 = 0.5944$

0.5944 = 59.44% probability that the team has at least 2 grade 11 students

5 0

3 years ago