Hey there :) I'm pretty sure that your answer is D) ∠S ≅ <span>∠Y because corresponding angles of similar triangles are congruent.
I think that it is the answer because if you shift your paper around, and look at the angles from different views, you can tell that angles S and Y are congruent, or the same, because of the way that both angles are at the end of the longer sides of both triangles.
So, your answer is D!
~Hope this helped!~</span>
Answer:
see below
Step-by-step explanation:
A proportional relationship has a graph that <em>always goes through the origin</em>. This fact by itself eliminates all the wrong answers.
A slope of 2/3 means the rise is 2 for each horizontal run to the right of 3. The two given points are 2 vertical units and 3 horizontal units apart, demonstrating a slope of 2/3.
For the first 6 trips she walked 3.2 kilometers and for the next 6 she made another 3.2 which would be 6.4 kilometers for 12 trips now she made 3 more trips which is half of the amount she originally did so it would be half of the distance also so 3.2 divided by 2 is 1.6 kilometers so for the last 3 trips she walked 1.6 kilometers. now add up all the distance she walked so 6.4 kilometers for the 12 trips plus the 1.6 for the other 3 trips is 8 kilometers in total. she walked 8 kilometers after 15 trips.
The slope of f(x) is 10 and the slope of g(x) is 5; g(x) has the greater y-intercept.
To find the slope of f(x), we use the slope formula: m=(y₂-y₁)/(x₂-x₁) = (-1--11)/(0--1) = (-1+11)/(0+1) = 10/1 = 10.
To find the slope of g(x), we just look at the form it is in. It is written in slope-intercept form, y=mx+b, where m is the slope. The number in g(x) that would correspond to m is 5.
The y-intercept of f(x) is found by looking at the points. Any y-intercept will have an x-coordinate of 0; the only point like this in the table is (0, -1) so the y-intercept is -1.
For g(x), we again look at the form y=mx+b. The number that corresponds with b is the y-intercept; in this case, it is 1. 1>-1, so g(x) has the larger y-intercept.
