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Bas_tet [7]
3 years ago
7

One positive integer is 3 less than twice another. the sum of their squares is 233. find the integers.

Mathematics
1 answer:
lana66690 [7]3 years ago
4 0
Let the two integers be x and y
x-3= 2y
x=2y+3______(1)

x²+y²= 233_____(2)
sub eqn (1) into (2)
{2y+3}²+y²=233
4y² + 12y +9 +y²=233
5y²+12y+9-233=0
5y²+12y-224=0
y= -8 or 5.6
recall they are positive integers so y=5.6
now sub y=5.6 into eqn (1)
x=2(5.6)+3 = 11.2+3=14.2

the two integers are 14.2 and 5.6
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Marat540 [252]

Answer:

22 units

Step-by-step explanation:

The perimeter of a polygon is said to be the sum of the length of it's sides.

From the question, we have 5 vertices. This means the polygon is a pentagon. It's given vertices are

A = (−1, 3)

B = (−1, 6) ​

C = (2, 10)

D = (5, 6) ​​

E = (5, 3) ​

To find the distance between two points, we use the formula

d = √[(y2 - y1)² + (x2 - x1)²]

Between A and B, we have

d(ab) = √[(6 - 3)² + (-1 --1)²]

d(ab) = √(3²) + 0

d(ab) = √9 = 3

Between B and C, we have

d(bc) = √[(10 - 6)² + (2 --1)²]

d(bc) = √[4² + 3²]

d(bc) = √(16 + 9) = √25 = 5

Between C and D, we have

d(cd) = √[(6 - 10)² + (5 - 2)²]

d(cd) = √[(-4)² + 3²]

d(cd) = √(16 + 9) = √25 = 5

Between D and E, we have

d(de) = √[(3 - 6)² + (5 - 5)²]

d(de) = √(-3)² + 0

d(de) = √9 = 3

Between E and A, we have

d(ea) = √[(3 - 3)² + (5 --1)²]

d(ea) = √[0 + (6)²]

d(ea) = √36 = 6

The perimeter is given as

d(ab) + d(bc) + d(cd) + d(de) + d(ea) =

3 + 5 + 5 + 3 + 6 = 22 units

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2 years ago
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Alex
RS<span> ≅ </span><span>ST is the correct answer</span>
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5 0
2 years ago
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77julia77 [94]

Answer:

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Step-by-step explanation:

Use

PEMDAS:

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E Exponents (ie Powers and Square Roots, etc.)

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