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snow_tiger [21]
4 years ago
15

HALLLLPPP Let g(x) = 2x and h(x) = x^2 + 4. Evaluate each expression: g(-2) - h(4)

Mathematics
2 answers:
True [87]4 years ago
5 0

Answer:

-24

Step-by-step explanation:

g(-2) = 2(-2)

g(-2) = -4

h(4) = 4² + 4

h(4) = 16 + 4

h(4) = 20

g(-2) - h(4)

-4 - 20

= -24

oksano4ka [1.4K]4 years ago
5 0

Answer:

<h2>g(-2) - h(4) = - 24</h2>

Step-by-step explanation:

g(x) = 2x

To find g( -2) substitute - 2 into g(x)

That's

g( -2) = 2(-2) = - 4

h(x) = x² + 4

To find h(4) substitute 4 into h(x)

That's

h(4) = (4)² + 4 = 16 + 4 = 20

So

g(-2) - h(4) is

- 4 - 20

= - 24

Hope this helps you

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Answer:

The 80% confidence interval for difference between two means is (0.85, 1.55).

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for difference between two means is:

CI=(\bar x_{1}-\bar x_{2})\pm t_{\alpha/2,(n_{1}+n_{2}-2)}\times SE_{\bar x_{1}-\bar x_{2}}

Given:

\bar x_{1}=M_{1}=6.1\\\bar x_{2}=M_{2}=4.9\\SE_{\bar x_{1}-\bar x_{2}}=0.25

Confidence level = 80%

t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.20/2, (5+5-2)}=t_{0.10,8}=1.397

*Use a <em>t</em>-table for the critical value.

Compute the 80% confidence interval for difference between two means as follows:

CI=(6.1-4.9)\pm 1.397\times 0.25\\=1.2\pm 0.34925\\=(0.85075, 1.54925)\\\approx(0.85, 1.55)

Thus, the 80% confidence interval for difference between two means is (0.85, 1.55).

3 0
3 years ago
According to the rational root theorem, which is a factor of the polynomial f(x)=3x^3-5x^2-12x+20?
MakcuM [25]

Answer:

(x-2), (x+2), (3x-5)

Step-by-step explanation:

Factors of 3: ±1, ±3

Factors of 20: ±1, ±2, ±4, ±5, ±10, ±20

Possible factors of the polynomial: ±1, ±2, ±3, ±4, ±5, ±10, ±20, .... (there's a lot more but you probably do not need to list them all)

Pick a number to divide the polynomial by (I picked 2)

(3x³-5x²-12x+20)÷(x-2) = 3x²+x-10

So (x-2) is a factor of f(x) = 3x³-5x²-12x+20

Factor 3x²+x-10 = (3x-5)(x-2) these are the other factors of f(x) = 3x³-5x²-12x+20

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It’s 10.2040816 right!!!!
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Answer:

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