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Hunter-Best [27]

3 years ago

5

The table shows the number of coils in different lengths of a spring.The spring next to the table shows an example of a 2 inch s

pring with 14 coils

1 answer:

Nastasia [14]3 years ago

4 0

The answer is A: 1 coil in a spring that is 7 inches long

i am not sure so correct me if i am wrong

hope this helps

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Kyle sells used cars. He is paid $14/hour plus and 8% commission on sales. What dollar amount of car sales must Kyle make to ear

Kazeer [188]

First we have to find how much Kyle earned taking to consideration only 38h at work
So 38*14$=532$
Now, to find commission bonus we have to 1200-532=668
Finally, we can find what dollar amount of car Kyle must sell.
We know that 668 is 8% of that number. We can use proportion and cross multiplying, so:
8% ----------- 668
100% --------x
$x= \frac{100*668}{8}=8350$ $ - its the result.

3 0

3 years ago

What is the best estimate of the perimeter of the figure on the grid if each square has side lengths of 1 mm?

Wewaii [24]

Answer:

4mm

Step-by-step explanation:

you have to add both sides after substituting each of the 4 sides by 1mm

which gives you the total of 4

6 0

1 year ago

37. Verify Green's theorem in the plane for f (3x2- 8y2) dx + (4y - 6xy) dy, where C is the boundary of the

Nastasia [14]

I'll only look at (37) here, since

• (38) was addressed in 24438105

• (39) was addressed in 24434477

• (40) and (41) were both addressed in 24434541

In both parts, we're considering the line integral

$\displaystyle \int_C (3x^2-8y^2)\,\mathrm dx + (4y-6xy)\,\mathrm dy$

and I assume <em>C</em> has a positive orientation in both cases

(a) It looks like the region has the curves <em>y</em> = <em>x</em> and <em>y</em> = <em>x</em> ² as its boundary***, so that the interior of <em>C</em> is the set <em>D</em> given by

$D = \left\{(x,y) \mid 0\le x\le1 \text{ and }x^2\le y\le x\right\}$

• Compute the line integral directly by splitting up <em>C</em> into two component curves,

<em>C₁ </em>: <em>x</em> = <em>t</em> and <em>y</em> = <em>t</em> ² with 0 ≤ <em>t</em> ≤ 1

<em>C₂</em> : <em>x</em> = 1 - <em>t</em> and <em>y</em> = 1 - <em>t</em> with 0 ≤ <em>t</em> ≤ 1

Then

$\displaystyle \int_C = \int_{C_1} + \int_{C_2} \\\\ = \int_0^1 \left((3t^2-8t^4)+(4t^2-6t^3)(2t))\right)\,\mathrm dt \\+ \int_0^1 \left((-5(1-t)^2)(-1)+(4(1-t)-6(1-t)^2)(-1)\right)\,\mathrm dt \\\\ = \int_0^1 (7-18t+14t^2+8t^3-20t^4)\,\mathrm dt = \boxed{\frac23}$

*** Obviously this interpretation is incorrect if the solution is supposed to be 3/2, so make the appropriate adjustment when you work this out for yourself.

• Compute the same integral using Green's theorem:

$\displaystyle \int_C (3x^2-8y^2)\,\mathrm dx + (4y-6xy)\,\mathrm dy = \iint_D \frac{\partial(4y-6xy)}{\partial x} - \frac{\partial(3x^2-8y^2)}{\partial y}\,\mathrm dx\,\mathrm dy \\\\ = \int_0^1\int_{x^2}^x 10y\,\mathrm dy\,\mathrm dx = \boxed{\frac23}$

(b) <em>C</em> is the boundary of the region

$D = \left\{(x,y) \mid 0\le x\le 1\text{ and }0\le y\le1-x\right\}$

• Compute the line integral directly, splitting up <em>C</em> into 3 components,

<em>C₁</em> : <em>x</em> = <em>t</em> and <em>y</em> = 0 with 0 ≤ <em>t</em> ≤ 1

<em>C₂</em> : <em>x</em> = 1 - <em>t</em> and <em>y</em> = <em>t</em> with 0 ≤ <em>t</em> ≤ 1

<em>C₃</em> : <em>x</em> = 0 and <em>y</em> = 1 - <em>t</em> with 0 ≤ <em>t</em> ≤ 1

Then

$\displaystyle \int_C = \int_{C_1} + \int_{C_2} + \int_{C_3} \\\\ = \int_0^1 3t^2\,\mathrm dt + \int_0^1 (11t^2+4t-3)\,\mathrm dt + \int_0^1(4t-4)\,\mathrm dt \\\\ = \int_0^1 (14t^2+8t-7)\,\mathrm dt = \boxed{\frac53}$

• Using Green's theorem:

$\displaystyle \int_C (3x^2-8y^2)\,\mathrm dx + (4y-6xy)\,\mathrm dx = \int_0^1\int_0^{1-x}10y\,\mathrm dy\,\mathrm dx = \boxed{\frac53}$

4 0

3 years ago

What is 26.73 rounded to the nearest decimal

Goshia [24]

I think it's 26.70 if I remember what a decimal is.

5 0

3 years ago

A shopkeeper purchased 60 pencil boxes for 4.500 and sold at the rate of 4.125 for 50 pencil boxes. How

VARVARA [1.3K]

Answer: 10%

Step-by-step explanation:

Since the shopkeeper purchased 60 pencil boxes for 4,500, he purchased them at the rate of:

= 4500 / 60

= 85 per pencil box

If the shopkeeper sold them at the rate of 4,125 for 50 pencil boxes, then he sold them at the rate of:

= 4125 / 50

= 82.50 per pencil box.

Therefore the percentage profit will be:

= Gain / Cost price × 100

= (82.50 - 75) / 75 × 100

= 7.5/75 × 100

= 10%

8 0

2 years ago