Answer:
OPTION B) 2ab
Step-by-step explanation:
Given:
Side of larger square = (a + b) units
Side of smaller square = c units
To Find:
The area of all four triangles combined = ?
Solution:
a^2 + b^2 = c^2 (Pythagoras theorem) -(1)
The area of all four triangles combined = Area of larger square - Area of smaller square
The area of all four triangles combined = (a + b)^2 - c^2
The area of all four triangles combined = a^2 + b^2 + 2ab - (a^2 + b^2) {By (1)}
The area of all four triangles combined = a^2 + b^2 + 2ab - a^2 - b^2
The area of all four triangles combined = a^2 - a^2 + b^2 - b^2 + 2ab
Therefore, The area of all four triangles combined = 2ab sq. units
OPTION B) 2ab
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Answer:
72
Step-by-step explanation:
Answer:
8
Step-by-step explanation:
Answer:
See attached for a graph
Step-by-step explanation:
We're going to plot sea level as y=0 and a depth of 8 meters as y=-8.
The problem statement tells you the initial point (x=0) is at normal ocean depth (y=-8), so the first point you put into your sine tool is ...
(x, y) = (0, -8)
The buoy takes 16 seconds to go from a high point to a low point, so the time to the first high point is half that, or x=8 seconds. That high point is 5 meters above its average depth, so is at y=-3.
The second point you will put into your sine tool is ...
(x, y) = (8, -3)
<span>Area of the base = 3*4 / 2 = 6
</span><span>Area of BOTH bases = 12 sq inches
Area of one face = 3 * 7 = 21 sq inches
</span>Area of 2nd face = 4 * 7 = 28 <span>sq inches
</span>Area of 3rd face = 5 * 7 = 35 <span>sq inches
TOTAL Area = 96 </span><span>sq inches</span>