<h2>
Answer with explanation:</h2>
Given : Sample size 
Sample mean : 
Sample standard deviation : 
Let 
be the population mean of "like" ratings of male dates made by the female dates.
As per question ,
Null hypothesis : 
Alternative hypothesis : 
, It means the test is a one-tailed t-test. ( we use t-test when population standard deviation is unknown.)
Test statistic:
For 0.05 significance and df =188 (df=n-1) p-value = .001582. [By t-table]
Since .001582< 0.05
Decision: p-value < significance level , that means there is statistical significance, so we reject the null hypothesis.
Conclusion : We support the claim at 5% significance that t the population mean of such ratings is less than 8.00.
Answer:
8
Step-by-step explanation:
y = (-3/4)x + c
Sub (11,-1) into the equtaion
-1 = (-3/4)(11) + c
c = 29/4
y = (-3/4)x + 29/4
when x = -1,
y = (-3/4)(-1) + 29/4
y = 8
r = 8
Answer:
y=3/2x - 5
Step-by-step explanation:
Subtract the 2y to move it to the other side
Subtract the 3x to move it to the other side
you get the equation of -2y=-3x + 10
Divide by -2
These are steps to help youu do distributive property with variables.
Answer:
x=4
Step-by-step explanation:
