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dexar [7]
3 years ago
9

Pls help thirty points and will do branliest

Mathematics
1 answer:
Luba_88 [7]3 years ago
8 0

The dashed-line triangle is a dilation-reduction, and the scale factor is (1/3).  Note how the former triangle is 1/3 the size of the larger one.

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Identify a transformation of the function f(x) = x^2 by observing the equation of the function g(x) = (x - 6)^2
MArishka [77]

Answer:

B

Step-by-step explanation:

Anything inside the bracket affects x opposite of the sign.

Look at it as if you’re solving for x:

  • x-6=0
  • x=6

therefore x moves 6 units to the right.

3 0
3 years ago
A rectangular tank measuring 50 cm x 30 cm x 60 cm was completely filled with water. 1 5 of the water in the tank was transferre
Ierofanga [76]

Answer:

<em>72,000cm³</em>

Step-by-step explanation:

Volume of the rectangular tank = Length *  Width * Height

Given

Length = 50cm

Width = 30cm

Height = 60cm

Get the volume:

Volume = 50*30*60

Volume = 90,000cm³

Hence the volume of the rectangular tank is 90,000cm³.

If 1/5 of the volume of water was transferred to another tank, the volume transferred will be:

Amount transferred = 1/5 * 90,000

Amount transferred = 18000cm³

Amount left in the tank = 90,000 - 18,000

<em>Amount of water left in the tank = 72,000cm³</em>

5 0
3 years ago
17. Find the length of the midsegment XY.
fredd [130]
Xy = 12 because if you look at the pattern the top one is 16 and the bottom one is 8 so the middle of those would be 12.
4 0
3 years ago
If a salesperson sells 3/4 of an acre for $80,000, what was the price per square foot rounded to two decimal spaces?
Julli [10]
Now, recalling that for 1 yard, there are 3 feet, therefore  \bf \begin{array}{ll}&#10;yards&feet\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;1yd&3ft\\&#10;(1yd)^2&(3ft)^2\\&#10;yd^2&3^2ft^2\\&#10;&9ft^2&#10;\end{array}

and keeping in mind that, there are 4840 yd² in 1 acre, then 

\bf \cfrac{\quad \frac{3}{4}~\underline{acre}\quad }{80000~\$}\cdot \cfrac{4840~\underline{yd^2}}{\underline{acre}}\cdot \cfrac{9~ft^2}{\underline{yd^2}}\implies \cfrac{\frac{3}{4}\cdot4840\cdot  9~ft^2}{80000~\$}\implies \cfrac{\frac{130680}{4}}{80000}&#10;\\\\\\&#10;\cfrac{\frac{130680}{4}}{\frac{80000}{1}}\implies \cfrac{130680}{4}\cdot \cfrac{1}{80000}\implies \cfrac{3267}{8000}~\frac{ft^2}{\$}~\approx~ 0.408375 ~\frac{ft^2}{\$}
5 0
3 years ago
A traffic light at a certain intersection is green 50% of the time, yellow 10% of the time, and red 40% of the time. A car appro
kati45 [8]

Answer:

6.4\times 10^{-5} = 0.000064 = 0.0064\%.

Step-by-step explanation:

Probability that the car encounters a green light on the first day: 50 \% = 0.5.

To meet the question's conditions, the car needs to encounter another green light on the second day. Given that the colors of the light on each day are "independent," the chance that there's a green light followed by another green light will be

(0.5) \times 0.5 = 0.25.

  • Condition is met on the first two days and green light on the third day: (0.5 \times 0.5) \times 0.5 = 0.125.
  • Condition is met on the first three days and green light on the fourth day:   (0.5 \times 0.5 \times 0.5) \times 0.5.

To meet the condition on the fifth day, there needs to be a yellow light. The probability that the condition is met on the first four days and on the fifth day will be (0.5 \times 0.5 \times 0.5 \times 0.5) \times 0.1 = 0.5^{4} \times 0.1.

To meet the condition on the sixth day, all prior days should meet the conditions. Besides, there needs to be a red light on the sixth day. (0.5^{4} \times 0.1) \times 0.4

  • Seventh day: (0.5^{4} \times 0.1 \times 0.4 ) \times 0.4
  • Eighth day: (0.5^{4} \times 0.1 \times 0.4^2 ) \times 0.4
  • Ninth day: (0.5^{4} \times 0.1 \times 0.4^3 ) \times 0.4
  • Tenth day: (0.5^{4} \times 0.1 \times 0.4^4 ) \times 0.4 = 0.5^{4} \times 0.1 \times 0.4^{5}

The question asks that the condition be met on all ten days. As a result, the probability of meeting the condition will be equal to the probability on the tenth day: 0.5^{4} \times 0.1 \times 0.4^{5} = 6.4\times 10^{-5} = 0.000064 = 0.0064\%.

6 0
3 years ago
Read 2 more answers
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