Answer:
a. a[1] = 3; a[n] = 2a[n-1]
b. a[n] = 3·2^(n-1)
c. a[15] = 49,152
Step-by-step explanation:
Each term of the given sequence is 2 times the previous term. (This description is the basis of the recursive formula.) That is, the terms of the given sequence have a common ratio of 2. This means the sequence is geometric, so the formulas for explicit and recursive rules for a geometric sequence apply.
The first term is 3, and the common ratio is 2.
<h3>(a)</h3>
The recursive rule is ...
a[1] = 3
a[n] = 2×a[n-1]
__
<h3>(b)</h3>
The explicit rule is ...
a[n] = a[1]×r^(n-1)
a[n] = 3×2^(n-1)
__
<h3>(c)</h3>
The 15th term is ...
a[15] = 3×2^(15-1) = 3×2^14
a[15] = 49,152
My answer is isn't on the choices and I can't show you how I got it. My answer is in the attached files.
Answer:
A(t)= 18000(0.988)^t
Step-by-step explanation:
Given data
Ryan bought a brand new car for $18,000
Its value depreciated at a rate of 1.2%
Let us use the compound expression
A= P(1-r)^t
substitute
A= 18000(1-0.012)^t
A(t)= 18000(0.988)^t
Hence the expression is A(t)= 18000(0.988)^t
I’m pretty sure a is always and b is sometimes.
Answer:
14
Step-by-step explanation:
20-6=14
x=14
