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svetlana [45]
3 years ago
8

HELP IM LITERALLY IN CLASS AND IM TAKING A TEST

Mathematics
2 answers:
svlad2 [7]3 years ago
8 0
The equation of the line is y = (-1/2)x - 1

Umnica [9.8K]3 years ago
6 0
I wouldn’t trust the links to a “photo” like the people in the comments said. If you give me the equation of the line the question is taking about I could solve it for you.
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Factor x^3y^6 + 27z^42
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(xy^2 + 3z^14)(x^2y^4 - 3xy^2z^14 + 9z^28)
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3 years ago
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Nina is 10 years younger than Deepak. Deepak is 3 times as old an Nina. Which system of equations can be used to find d, Deepak’
nevsk [136]
The answer would be the first choice which is d = n + 10, d = 3n. Deepak is 10 years older than Nina, so knowing this, the equation cancels out B and D. And Deepak is 3 times Nina's age, not Nina's age is three times Deepak's. It is not the other way around. 
3 0
3 years ago
In the above figure, m∠A = 26° and m∠B = (2x + 16)°. If angles A and B are complementary angles, what are the value of x and the
BartSMP [9]

Answer:

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Hope this helps!

8 0
2 years ago
bill spent $19 at starbucks on a coffee and some cookies. if the coffee cost $5 each cookie cost $2, how many cookies did he buy
Nataliya [291]

Answer:

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6 0
3 years ago
The area of a rectangle is 300 square centimeters. If the sides of the rectangle are given as 5 centimeters and <img src="https:
joja [24]
<em>x</em> is 1000, and the other side of the rectangle is 60 cm.
Area is found by multiplying length by width.  Using the sides we know we have
300=5(\sqrt{x+2600})
We divide both sides by 5:
\frac{300}{5}=\frac{5\sqrt{x+2600}}{5}&#10;\\&#10;\\60=\sqrt{x+2600}
To "undo" a square root, we square both sides:
60^2=(\sqrt{x+2600})^2&#10;\\&#10;\\3600=x+2600
Subtract 2600 from both sides:
3600-2600=x+2600-2600
1000=x
Now we substitute this into the side with x:
\sqrt{x+2600}=\sqrt{1000+2600}=\sqrt{3600}=60
3 0
3 years ago
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