Answer:
it is the second one i had this question. mark as brainliest
Step-by-step explanation:
Answer:
the 4th answer I(x) = P(x-4)
Step-by-step explanation:
the first 2 options are out, because just adding values to the functional result values changes the y value, and the curve is pushed up or down. but not to the side.
just imagine
I(x) = P(x-4) means that the function value of previously at x-4 happens now at x. 4 units "later" (or more to the right).
"x+4" would make the functional value at previously x+4 happen now at x. so, everything would shift to the left (happen "earlier").
therefore, the 4th answer option is correct.
Remember that a quadratic equation is a parabola. The equation is of the type y = Ax^2 + Bx + C
A linear equation is a straight line. The equation is of the type y = MX + N
The soluction of that system is Ax^2 + Bx + C = MX + N
=> Ax^2 + (B-M)x + (C-N) = 0
That is a quadratic equation.
A quadratic equation may have 0, 1 or 2 real solutions. Those are all the possibilitis.
So you must select 0, 1 and 2.
You can also get to that conclusion if you draw a parabola and figure out now many point of it you can intersect with a straight line.
You will realize that depending of the straight line position it can intersect the parabola in none point, or one point or two points.
