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Sveta_85 [38]
2 years ago
10

Ms. Alba is on a business trip. Her company gave her $20 for 6 meals. She has spent $95 and has eaten 5 meals. Find x, the amoun

t Alba might spend on her next meal.
A: x ≤ 25

B: x ≥ 25

C: x ≤ 26

D: x ≥ 26
Mathematics
1 answer:
ipn [44]2 years ago
4 0

Answer:

A

Step-by-step explanation:

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Carmin 151000(1+9.9%/12)^204=??? richie 116000(1+9.9%/12)^204=???
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3 years ago
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Urgent help needed algebra 2
blsea [12.9K]

The solution of the given equation (x + 5) - ( 2x - 3) = 6 is 2.

<h3>What is a linear equation?</h3>

A linear equation is an equation that has the variable of the highest power of 1.

The standard form of a linear equation is of the form Ax + B = 0.

The given equation is;

(x + 5) - ( 2x - 3) = 6

To solve;

(x + 5) - ( 2x - 3) = 6

Distribute the negative;

(x + 5) - 2x + 3 = 6

we need to get the like terms together;

x - 2x + 5+ 3 = 6

-x + 8 = 6

Subtract 8 from both sides, we get;

-x = -2

x = 2

Hence, the solution of the given equation is 2.

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3 0
2 years ago
An airplane has 100 seats for passengers. Assume that the probability that a person holding a ticket appears for the flight is 0
zmey [24]

Answer:

96.33% probability that everyone who appears for the flight will get a seat

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 105, p = 0.9

So

\mu = E(X) = np = 105*0.9 = 94.5

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{105*0.9*0.1} = 3.07

What is the probability that everyone who appears for the flight will get a seat

100 or less people appearing to the flight, which is the pvalue of Z when X = 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{100 - 94.5}{3.07}

Z = 1.79

Z = 1.79 has a pvalue of 0.9633

96.33% probability that everyone who appears for the flight will get a seat

7 0
3 years ago
Help please!! Thank you :)
Softa [21]
My answer that i have gotten is 280
3 0
3 years ago
Carrie spent 
Pavel [41]

24 dollars.

1/4 + 1/3 = 3/12 + 4/12 = 7/12

7/12 a + 8 = 22

7/12 a = 14

a = 14 x 12/7

a = 24 dollars

6 0
3 years ago
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