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ss7ja [257]
3 years ago
11

Triangle abc is a right traingle if side ac=7 and side bc= 10 what is the measure of ab?

Mathematics
1 answer:
Artist 52 [7]3 years ago
7 0
<span>Use the Pythagorean theorem for the right triangle ABC, where

AB is the hypotenuse of the triangle;

AC and BC are the other two sides.


So,

(AC)^{2}+(BC)^{2}=(AB)^{2}\\\\ 7^{2}+10^{2}=(AB)^{2}\\\\ (AB)^{2}=49+100\\\\ (AB)^{2}=149\\\\ AB=\sqrt{149}

</span>
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This is going to be tricky pls solve from i ready
shutvik [7]

Answer:

4/10 meters

Step-by-step explanation:

Original Length : 7/10 meters

Remaining Length after cut : 3/10 meters

amount cut off = original length - remaining length

= 7/10 - 3/10

= (7-3)/ 10

= 4/10

3 0
3 years ago
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Qhat is the measure of each interior angle of a regular hexagon
Dmitrij [34]

120°

the sum of the interior angles of a polygon = 180°( n - 2)

where n is the number of sides

here n = 6 ⇒ sum = 180° × 4 = 720°

thus each interior angle = \frac{720}{6} = 120°


7 0
3 years ago
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Which property of polynomial addition says that the sum of two polynomials
ArbitrLikvidat [17]

Answer:

The property of polynomial addition that says that the sum of two polynomial is always a polynomial is called closure property of addition or under addition.

Polynomials are closed under addition because when you add polynomials the letters and their exponents do no change, you just add the coefficients of the like terms (those with same letters raised to the same exponents), so the result will be other polynomial of the same kind, except for the terms that cancel (positive with negative) which does not change the fact that the result is still a polynomial.

In mathematics the closure property means that the result of an operation over a kind of "number" will result in a "number" of the same kind.

7 0
3 years ago
√200 in consecutive integers and in simplified form
myrzilka [38]
√200 = √2·100 = √2 · √100 = 10√2
4 0
3 years ago
Marisol noticed that she does not have a common factor.
konstantin123 [22]

Answer:  option 2 describes best

Step-by-step explanation:Given Marisol grouped the terms and factored the GCF out of the groups of the polynomial 6x3 – 22x2 – 9x + 33. Her work is shown.  

Step 1: (6x3 – 22x2) – (9x + 33)

Step 2: 2x2(3x – 11) – 3(3x + 11)

Marisol noticed that she does not have a common factor. Which accurately describes what Marisol should do next?

Marisol should realize that her work shows that the polynomial is prime.

Marisol should go back and group the terms in Step 1 as (6x3 – 22x2) – (9x – 33).

Marisol should go back and group the terms in Step 1 as (6x3 – 22x2) + (9x – 33).

Marisol should refactor the expression in Step 2 as 2x2(3x + 11) – 3(3x + 11).

According to question Marisol grouped the terms and has done factorisation of the given polynomial 6x^3 – 22x^2 – 9x + 33.

In step 1 she has written as (6x^3 – 22x^2) – (9x + 33)

Marisol has to go to step 1 in order to correct her mistake. She has to group the expression as (6x^3 – 22x^2) – (9x – 33) so that she will be able to get the expression as

6x^3 – 22x^2 – 9x + 33 after opening the brackets.

4 0
3 years ago
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