Hey there :)
gh² and 2g³h
The common here are g and h because the factor g and h appear in both terms
Therefore, the GCF is gh
Change the mixed fractions to an improper fraction.
4 5/7 = 32/7
1 6/7 = 13/7
Now you can easily subtract since both fractions have common denominators
32/7 - 13/7
(Think: 32 - 13 = 19)
Change the improper fraction to a mixed fraction
19/7 = 2 5/7
Answer: 2 5/7
Hope I helped =)
Answer:
a/8 or a over 8 hope this helps
Step-by-step explanation:
Given :
A right angle triangle ABC .
To Find :
The perimeter of ABC .
Solution :
Since, triangle ABC is right angled and angle ∠ABC is 46° .
So, AC = AB cos 46° = 7.64 units.
Also, CB = AB sin 46° = 7.91 units.
Therefore, the perimeter of ΔABC is :
P = 11 + 7.64 + 7.91 units
P = 26.55 units
Hence, this is the required solution.
