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topjm [15]
3 years ago
11

HELP ME NOW PLEASE NOW ADGAFDKD;LHJ!!!!!! PLEASE AND THANK YOU :)))))

Mathematics
1 answer:
Eddi Din [679]3 years ago
7 0

I got D.

There's a few ways to solve it; I prefer using tables, but there are functions on a TI-84 that'll do it for you too. The logic here is, you have a standard normal distribution which means right away, the mean is 0 and the standard deviation is 1. This means you can use a Z table that helps you calculate the area beneath a normal curve for a range of values. Here, your two Z scores are -1.21 and .84. You might notice that this table doesn't account for negative values, but the cool thing about a normal distribution is that we can assume symmetry, so you can just look for 1.21 and call it good. The actual calculation here is:

1 - Z-score of 1.21 - Z-score .84 ... use the table or calculator

1 - .1131 - .2005 = .6864

Because this table calculates areas to the RIGHT of the mean, you have to play around with it a little to get the bit in the middle that your graph asks for. You subtract from 1 to make sure you're getting the area in the middle and not the area of the tails in this problem.

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Table:

x      y

-3    0.5

-2    1

-1     2.5

0      5

1      8.5

Now, y = ax^2 + bx + c

Start replacing x = 0 and y = 5

5 = a(0) + b(0) + c => c = 5.

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Solve the system

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=>

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-------------------------

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