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2 years ago

2nd question! BRAINLIEST and high points :D

Mathematics

1 answer:

Vesna [10]2 years ago

8 0

Answer:

Step-by-step explanation:

One side is 60 so the other side is 60

X=20

4(20)-20=60

60=(4(20)-20)

60=80-20

60=60

kinda got a bit dum

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Bill and Joe have 60 dollars between them. Bill has half as much as Joe. How much does Bill have?

Katyanochek1 [597]

Bill and Joe have 60 dollars between them. Bill has half as much as Joe.

so Bill = B and Joe = J

20 (B) + 40 (J) = 60

Bill has half the amount of Joe, and so 40/2 = 20

subtract 60 from 20 (the answer for Bill) and you get 40, (the answer for Joe)

hope this helps

6 0

3 years ago

if 42% of a crowd of 3850 at a football match were females, how many females attended the football game?

sweet [91]

Answer: 1617

Step-by-step explanation:

You would need to find 42% of 3850

Convert 42% into decimal:

42/100 = 0.42

Multiply:

0.42*3850

= 1617

Therefore, there were 1617 females that attended the game

7 0

2 years ago

Read 2 more answers

For triangle ABC with sides a,b and c the law of cosines states

grigory [225]

Answer:

SAS

Step-by-step explanation:

Looking for the third side given the other two sides and the angle between them

c² = a² + b² - 2abcosC

6 0

2 years ago

pls help!? with all 4 Questions I would rlly appreciate your help thx to plp who help me I will improve on my math and be way be

aliina [53]

7.6=w/12
w=7.6(12)
w=91.2

x/2=20
x=20(2)
x=40

8.3x=41
x=41(8.3)
x=340.3

54=r/3
r=54(3)
r=162

6 0

3 years ago

Of 450 college students, 110 are enrolled in math, 205 are enrolled in English, and 50 are enrolled in both. If a student is sel

likoan [24]

Answer:

Step-by-step explanation:

Given that Of 450 college students, 110 are enrolled in math, 205 are enrolled in English, and 50 are enrolled in both. If a student is selected at random

the probability

(a) The student is enrolled in mathematics= $\frac{110}{450} =0.244\\$