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1 year ago

In Arizona, a minimum temperature of -40°F was recorded at Hawley Lake 1971. A maximum recorded

1 answer:

3 0

I Believe it would be 53 because it’s asking what is the difference and they difference would have to be 53 your going from a negative to a positive

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A multivitamin tablet contains 16.5 . How much vitamins c does a bottle of 30 tablets contain? Write your answer in grams?

AURORKA [14]

Multiply 16.5 by 30

16.5x30=495

8 0

2 years ago

hi! i was wondering if i could have some help and maybe someone do 2 and another do 2 idk but thank u sm

Margarita [4]

Answer:

1) 5 2) 7 3) 9 4) 8

Step-by-step explanation:

you add and subtract the numbers, for example, number 1, the total is 9 and it shows 4 so 5. Or 3, K to I is 3 and 11 (the total) minus 3 equals 8, plus the 1 so 9. Hope this helps! Have a good day! :)

8 0

2 years ago

For each level of precision, find the required sample size to estimate the mean starting salary for a new CPA with 95 percent co

Rzqust [24]

Answer:

(a) Margin of error ( E) = $2,000 , n = 54

(b) Margin of error ( E) = $1,000 , n = 216

(c) Margin of error ( E) = $500 , n= 864

Step-by-step explanation:

Given -

Standard deviation $\sigma$ = $7,500

$\alpha$ = 1 - confidence interval = 1 - .95 = .05

$Z_{\frac{\alpha}{2}}$ = $Z_{\frac{.05}{2}}$ = 1.96

let sample size is n

(a) Margin of error ( E) = $2,000

Margin of error ( E) = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

E = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$E^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{2000^{2}} \times 7500^{2}$

n = 54.0225

n = 54 ( approximately)

(b) Margin of error ( E) = $1,000

E = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

1000 = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$1000^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{1000^{2}} \times 7500^{2}$

n = 216

E = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

500 = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$500^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{500^{2}} \times 7500^{2}$

n = 864

7 0

3 years ago

Drag and drop the number to match the division problem to its quotient.

enyata [817]

C I'm using the calculator and the other ones don't make sense

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3 years ago

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Find the midpoint of the segment with the given endpoint M(-2,1) and N (-3,2)

Aleks04 [339]

(-2,1)
(-2.5,1.5)
(-3,2)

3 0

3 years ago