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Zina [86]
3 years ago
6

You want to estimate the number of students in a junior high school who ride the school bus. which sample is unbiased?​

Mathematics
1 answer:
Vika [28.1K]3 years ago
8 0

Answer:

Option B - 90 students at random during lunch

Step-by-step

An unbiased sample is defined as:

A sample is an unbiased sample if every individual or the element in the population has an equal chance of being selected.

Based on this, we can eliminate:

Option A) - It prevents non-eighth-graders of the school from being represented.

Option C) - Students in a hallway might take a particular class together/may be of the same grade. This gives them an unfair advantage.

Option D) - All students who are not in chorus are not represented in this set.

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That's two half lives. 5/8 * 2 * 2 = 20/8 = 5/2 pounds7/8 * 2 * 2 = 28/8 = 7/2 pounds
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Please help!!!!!!!!!!!!!!!!!!!!!!!!!! answer both
weeeeeb [17]

<u>Solution </u><u>1</u><u> </u><u>:</u><u>-</u>

Given expression ,

\implies 13^{\frac{3}{4}}

We know that, a^{\frac{m}{n}} = \sqrt[n]{a^m}

Therefore , this can be written as ,

\implies \sqrt[4]{13^3}

<u>Solution</u><u> </u><u>2</u><u>:</u><u>-</u>

Given expression ,

\implies \sqrt[3]{24^{10}}

We know that,a^{\frac{m}{n}} = \sqrt[n]{a^m}

Therefore, this can be written as ,

\implies 24^{\frac{10}{3}}

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2 years ago
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Field book of an land is given in the figure. It is divided into 4 plots . Plot I is a right triangle , plot II is an equilatera
Kazeer [188]

Answer:

Total area = 237.09 cm²

Step-by-step explanation:

Given question is incomplete; here is the complete question.

Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)

From the figure attached,

Area of the right triangle I = \frac{1}{2}(\text{Base})\times (\text{Height})

Area of ΔADC = \frac{1}{2}(\text{CD})(\text{AD})

                        = \frac{1}{2}(\sqrt{(AC)^2-(AD)^2})(\text{AD})

                        = \frac{1}{2}(\sqrt{(13)^2-(19-7)^2} )(19-7)

                        = \frac{1}{2}(\sqrt{169-144})(12)

                        = \frac{1}{2}(5)(12)

                        = 30 cm²

Area of equilateral triangle II = \frac{\sqrt{3} }{4}(\text{Side})^2

Area of equilateral triangle II = \frac{\sqrt{3}}{4}(13)^2

                                                = \frac{(1.73)(169)}{4}

                                                = 73.0925

                                                ≈ 73.09 cm²

Area of rectangle III = Length × width

                                 = CF × CD

                                 = 7 × 5

                                 = 35 cm²

Area of trapezium EFGH = \frac{1}{2}(\text{EF}+\text{GH})(\text{FJ})

Since, GH = GJ + JK + KH

17 = \sqrt{9^{2}-x^{2}}+5+\sqrt{(15)^2-x^{2}}

12 = \sqrt{81-x^2}+\sqrt{225-x^2}

144 = (81 - x²) + (225 - x²) + 2\sqrt{(81-x^2)(225-x^2)}

144 - 306 = -2x² + 2\sqrt{(81-x^2)(225-x^2)}

-81 = -x² + \sqrt{(81-x^2)(225-x^2)}

(x² - 81)² = (81 - x²)(225 - x²)

x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴

144x² - 11664 = 0

x² = 81

x = 9 cm

Now area of plot IV = \frac{1}{2}(5+17)(9)

                                = 99 cm²

Total Area of the land = 30 + 73.09 + 35 + 99

                                    = 237.09 cm²

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3 years ago
The sum of 8 times a number and 5 is equal to 3
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8x+5=3
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Express the product of 2xsquared+6x-8 and x+3 in standard form
postnew [5]

Answer:

2x^3+12x^2+10x-24

Step-by-step explanation:

(2x^2+6x-8)(x+3)

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2x^3+6x^2+6x^2-8x+18x-24

2x^3+12x^2+10x-24

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3 years ago
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