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Mashcka [7]
3 years ago
15

Which equation is an identity?

Mathematics
2 answers:
AfilCa [17]3 years ago
5 0

Answer: The Answer is C. 2x+3+1/2 (4x+2)+2


Step-by-step explanation:


Scilla [17]3 years ago
5 0

For this case we have that an identity is an equation in which the left side of the equation is equal to the right side of the equation.

We then have the following equation:

2x + 3 = \frac {1} {2} (4x + 2) + 2

When applying the distributive property on the right side we have:

2x + 3 = \frac {1} {2} (4x) + \frac {1} {2} (2) + 2

Rewriting we have:

2x + 3 = 2x + 1 + 2\\2x + 3 = 2x + 3

We observe that both sides are equal. Therefore, the equation is an identity.

Answer:

2x + 3 = \frac {1} {2} (4x + 2) + 2

Option C


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Answer:

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Step-by-step explanation:

In a normal distribution, the interval (mean - 3*standard deviation, mean + 3*standard deviation) account for about 99.7% of the values. In this case mean + 3*standard deviation = $87.00 + 3*$36.00 = $195.00. So, it 's expected that this amount of money would be the largest individual customer bill.

4 0
3 years ago
If you toss three coins, what are the odds in favor of getting exactly two tails and one head?
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I think the answer is 3:5

7 0
3 years ago
X^4+2x^2-48=0 what is the solution set
jolli1 [7]

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Step-by-step explanation:

x^4 + 2x^2-48=0

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6 0
3 years ago
Given that (y+z), (y+3) and (2y^2-1) are consecutive terms of an arithmetic progression. Find the possible values of y
Sphinxa [80]

Answer:

This problem actually says:

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Now, the difference between two consecutive terms in an arithmetic progression is always the same, so we have:

(y + 3) - (y +2) = D

(2*y^2 - 1) - (y + 3) = D

From the first equation we have:

y + 3 - y - 2 = 1  = D

Now we can replace it in the other equation:

2*y^2 - 1 - y - 3 = 1

2*y^2 - y - 5 = 0

Now we need to solve that equation to find the possible values of y.

To solve a quadratic equation of the form:

a*x^2 + b*x + c = 0, we can use the Bhaskara's equation:

y = \frac{-b +- \sqrt{b^2 -4*a*c} }{2*a}

in this case, the solutions are:

y = \frac{1 +-\sqrt[]{(-1)^2 - 4*2*(-5)} }{2*2}  = \frac{1 +- \sqrt{61} }{4} = \frac{1+-6.4}{4}

Then the possible values of y are:

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5 0
4 years ago
A line contains the following points left to right: R, T, U, S. The space between R and T is 12 units. The space between R and S
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Step-by-step explanation:

8 0
3 years ago
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