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2 years ago

Find the inverse of g(x)=4/x+2

Mathematics

1 answer:

yulyashka [42]2 years ago

7 0

I think it’s g^-1(x)= -2x+4

The “^” means exponent to -1 is the exponent of g

Hope I’m right !!

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What is the volume of the cylinder if the height is 2x+7 and the radius is x-3

shusha [124]

Answer:

Therefore the volume of the cylinder $=\pi(2x^3-5x^2-24x+63)$ cubic units

Step-by-step explanation:

Given height of a cylinder is (h) =2x+7

and radius (r)= x-3

Volume of the cylinder = $\pi r^2 h$

$=\pi (x-3)^2(2x+7)$

$=\pi (x^2-6x+9)(2x+7)$

$=\pi (2x^3-12x^2+18x+7x^2-42x+63)$

$=\pi(2x^3-5x^2-24x+63)$ cubic units

Therefore the volume of the cylinder $=\pi(2x^3-5x^2-24x+63)$ cubic units

5 0

3 years ago

The area of a square is found by squaring one of its sides, (A = s2). A certain square has an area of z2 + 18z + 81. Factor the

masya89 [10]

Here is your answer

Given area is

z^2 + 18z + 81

= z^2 + 2× z × 9 + 9^2

[using (a+b)^2= a^2 + 2ab + b^2], we get

= (z+9)^2

we know that area of a square is represented by side^2.

So, here

Side of square is

$z+9$

HOPE IT IS USEFUL

7 0

3 years ago

Read 2 more answers

What is 62 rounded to the nearest hundred .

kiruha [24]

100 i hope it helped

4 0

3 years ago

Read 2 more answers

What work do i need to show?

stealth61 [152]

You have to show finding the square root of it ______ ___ __
√144x^2 + √225 = √0
which will give you 12x+15=0
12x=15
x=5/4

4 0

3 years ago

You deposit 2000 in account A, which pays 2.25% annual interest compounded monthly. You deposit another 2000 in account b, which

stellarik [79]

To model this situation, we are going to use the compound interest formula: $A=P(1+ \frac{r}{n} )^{nt}$
where
$A$ is the final amount after $t$ years
$P$ is the initial deposit
$r$ is the interest rate in decimal form
$n$ is the number of times the interest is compounded per year
$t$ is the time in years

For account A:
We know for our problem that $P=2000$ and $r= \frac{2.25}{100} =0.0225$ . Since the interest is compounded monthly, it is compounded 12 times per year; therefore, $n=12$ . Lets replace those values in our formula:
$A=2000(1+ \frac{0.0225}{12} )^{12t}$

For account B:
$P=2000$ , $r= \frac{3}{100} =0.03$ , $n=12$ . Lest replace those values in our formula:
$A=2000(1+ \frac{0.03}{12} )^{12t}$

Since we want to find the time, $t$ , <span>when the sum of the balance in both accounts is at least 5000, we need to add both accounts and set that sum equal to 5000:
</span> $2000(1+ \frac{0.0225}{12} )^{12t}+2000(1+ \frac{0.03}{12} )^{12t}=5000$

Now that we have our equation, we just need to solve for $t$ :
$2000[(1+ \frac{0.0225}{12} )^{12t}+(1+ \frac{0.03}{12} )^{12t}]=5000$
$(1+ \frac{0.0225}{12} )^{12t}+(1+ \frac{0.03}{12} )^{12t}= \frac{5000} {2000}$
$(1.001875)^{12t}+(1.0025 )^{12t}= \frac{5}
{2}$
$ln(1.001875)^{12t}+ln(1.0025 )^{12t}=ln( \frac{5} {2})$
$12tln(1.001875)+12tln(1.0025 )=ln( \frac{5} {2})$
$t[12ln(1.001875)+12ln(1.0025 )]=ln( \frac{5} {2})$
$t= \frac{ln( \frac{5}{2} )}{12ln(1.001875)+12ln(1.0025 )}$
$17.47$

We can conclude that after 17.47 years <span>the sum of the balance in both accounts will be at least 5000.</span>

5 0

3 years ago