Answer:
You take the repeating group of digits and divide it by the same number of digits but formed only by 9s.
Step-by-step explanation:
Let's say you have 0.111111111111...., your repeating pattern is 1, that consists of one digit (1). You take that digit and you divide it by 9:
1/9 is the fraction equivalent to 0.111111111111111...
Let's say you have 0.12121212121212...., the repeating pattern is 12, that consists of 2 digits (12). You take those 2 digits and divide them by 99:
12/99 is the fraction equivalent to 0.12121212121212...
which can be reduced to 4/33
If you have 0.363363363363..., your repeating pattern is 363, which is 3 digits, so you divide 363by 999:
363/999 is the fraction equivalent to 0.363363363363...
which can be simplified to 121/333
Answer:
6(x^2-3)
Step-by-step explanation:
The class is weighted as follows:
60% Regular Tests
10% Final Exam
15% Project
15% Homework
The total weighted points possible for the class are as follows:
(100+100+100+100+100)*.6 + 100*.1 + 100*.15 + 100*.15 = 340
To calculate her individual final weighted grade we plug in her scores for each category and complete the following computation:
(92+83+77+84+82)*.6 + 88*.1 + 95*.15 + 77*.15 = 285.4
So her weighted grade percent would be 285.4/340 = 83.9% which is a B.
Answer:
66/54
Step-by-step explanation:
(a) The "average value" of a function over an interval [a,b] is defined to be
(1/(b-a)) times the integral of f from the limits x= a to x = b.
Now S = 200(5 - 9/(2+t))
The average value of S during the first year (from t = 0 months to t = 12 months) is then:
(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12
or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12
This equals 200/12 * (5t -9ln(2+t))
Evaluating this with the limits t= 0 to t = 12 gives:
708.113 units., which is the average value of S(t) during the first year.
(b). We need to find S'(t), and then equate this with the average value.
Now S'(t) = 1800/(t+2)^2
So you're left with solving 1800/(t+2)^2 = 708.113
<span>I'll leave that to you</span>
