You can solve using the pythagorean theorem which is
a^2+b^2=c^2 where a and b are the legs and c is the hypotenuse in a right triangle.
12^2+x^2=24^2
144+x^2=576
x^2=432
x =20.78 (approximately)
( y - 4 ) ( y² + 4 y + 16 ) =
= y³ + 4 y² + 16 y - 4 y² - 16 y - 64 = y³ - 64
If the result is the polynomial of the form:
y³ + 4 y² + a y - 4 y² - a y - 64
a = 16
Answer:
y =47.5.
Step-by-step explanation:
First eliminate the fractions by multiplying through by the LCM of 7 and 3 which is 21:
21* 6[y-2]/7-21*12 = 21*2[y-7]/3
18(y - 2) - 252 = 14(y - 7)
18y -36 - 252 = 14y - 98
18y - 14y = -98 + 36 + 252
4y = 190
y = 190/4
y = 47.5.
Answer:
x + 5 = 5
Step-by-step explanation:
Solution doesn't change as the x in the equation is 0 and the answer totals as 5 due to 5 plus 0 being 5
