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2 years ago

The number of numbers which are multiples of both 3 and 5 in the first 100 natural numbers is (a) 10 (b) 9 (C) 7 (d) 6

Mathematics

1 answer:

Virty [35]2 years ago

5 0

Answer:

it should be A I think try it and see if it that the answer I can't remember tho

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inessss [21]

Answer:

-------------

(x+2)(x-4)

Step-by-step explanation:

x+4 x+3

------------- * --------------

x^2+5x+6 x^2 -16

Factor

x+4 x+3

------------- * --------------

(x+3)(x+2) (x+4)(x-4)

Cancel like terms

1 1

------------- * --------------

(1)(x+2) (1)(x-4)

------------- x cannot equal -3, -4, -2, 4

(x+2)(x-4)

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2 years ago

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<h2><u>Solution</u></h2>

$\frac{4}{3} - 2 \\ \\ = \frac{4 - 6}{ 3} \\ \\ = \frac{ - 2}{3}$

<h3>Hope This Helps You ❤️</h3>

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3 years ago

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romanna [79]

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2 years ago

The number of numbers which are multiples of both 3 and 5 in the first 100 natural numbers is (a) 10 (b) 9 (C) 7 (d) 6​

The number of numbers which are multiples of both 3 and 5 in the first 100 natural numbers is (a) 10 (b) 9 (C) 7 (d) 6