The number of numbers which are multiples of both 3 and 5 in the first 100 natural numbers is (a) 10 (b) 9 (C) 7 (d) 6
1 answer:
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Answer:
b. How many ways arc there to go 12 miles?
≡ p(12) = 25
c. How many ways arc there to go 20 miles?
≡ p(20) = 131
d. How many ways arc there to go 22 miles?
≡p(22) 199
Step-by-step explanation:
a) supposed you walked for the first hour. Then you would have travelled 3 miles. if you jogged you would have covered 5miles and if you run you would have covered 10miles. now you have to decide how to run the rest miles from the n miles.
Thus, the number of ways one can cover n miles will be given by the recurrence relation
p(n) = p( n-3) + p( n-5) + p( n - 10)
now to solve the rest of the question, let us make a table which provides the number of ways for n = 1 to 22.
check the attachment for the table
b. How many ways arc there to go 12 miles?
≡ p(12) = 25
c. How many ways arc there to go 20 miles?
≡ p(20) = 131
d. How many ways arc there to go 22 miles?
≡p(22) 199
