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Tju [1.3M]
3 years ago
7

Can anyone help me with these three questions

Mathematics
1 answer:
iren2701 [21]3 years ago
5 0
Sure, what are the questions?
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In the rectangle below, EI = 2x+6, FI = 5x-6, and m ZIFE = 49º.
Reil [10]

Answer:

gdfhddfdhgbg

Step-by-step explanation:

6 0
3 years ago
Bethany has a circular table that she needs to carry inside her house to paint. Her front door is a rectangle and has a width of
RoseWind [281]
I thought I knew this but nvm
4 0
3 years ago
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Which is the equation of an ellipse with directrices at x = ±4 and foci at (2, 0) and (−2, 0)?
NemiM [27]

Answer:

x squared over 4 plus y squared over 8 equals 1

Step-by-step explanation:

The general equation of ellipse is given as;

(x²/a²) + (y²/b²) = 1

The coordinates of a foci are: (±c, 0) where;

c² = b² - a²

However, we know that equation of directrix is; x = ±a/e

Now, Directrix is given ±4

Thus, a/e = 4

a = 4e

We also know that c = ae from ellipse foci coordinates.

Thus, ae = 2

since ae = 2, then (4e)e = 2

4e² = 2

e² = 2/4

e = 1/2

Thus;

a = 4 × 1/2

a = 2

Since c² = b² - a²;

2² = b² - 2²

4 = b² - 4

b² = 8

From (x²/a²) + (y²/b²) = 1, we can put our values to get;

x²/4 + y²/8 = 1

6 0
3 years ago
Which graph shows the solution to the following system of inequalities x+y>4
mylen [45]

The solution to this system of inequalities x + y>4  , x + y <3 is Option A

The complete question is

Which graph shows the solution to this system of inequalities? x + y>4 x + y <3

The image are attached with the answer.

<h3>What are Inequality ?</h3>

When an expression is equated with another expression by an Inequality operator (< , >  < etc) then the mathematical statement formed is called Inequality.

The inequalities are

x+y>4

x + y <3

After plotting both the inequalities in the graph the following graph that is attached with the answer is obtained.

Therefore the correct answer is Option A

To know more about Inequalities

brainly.com/question/20383699

#SPJ1

5 0
2 years ago
If possible help me in this. I need to find the two odd numbers...​
Lelechka [254]

Part (a)

Consecutive odd integers are integers that odd and they follow one right after another. If x is odd, then x+2 is the next odd integer

For example, if x = 7, then x+2 = 9 is right after.

<h3>Answer:  x+2</h3>

========================================================

Part (b)

The consecutive odd integers we're dealing with are x and x+2.

Their squares are x^2 and (x+2)^2, and these squares add to 394.

<h3>Answer: x^2 + (x+2)^2 = 394</h3>

========================================================

Part (c)

We'll solve the equation we just set up.

x^2 + (x+2)^2 = 394

x^2 + x^2 + 4x + 4 = 394

2x^2+4x+4-394 = 0

2x^2+4x-390 = 0

2(x^2 + 2x - 195) = 0

x^2 + 2x - 195 = 0

You could factor this, but the quadratic formula avoids trial and error.

Use a = 1, b = 2, c = -195 in the quadratic formula.

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(2)\pm\sqrt{(2)^2-4(1)(-195)}}{2(1)}\\\\x = \frac{-2\pm\sqrt{784}}{2}\\\\x = \frac{-2\pm28}{2}\\\\x = \frac{-2+28}{2} \ \text{ or } \ x = \frac{-2-28}{2}\\\\x = \frac{26}{2} \ \text{ or } \ x = \frac{-30}{2}\\\\x = 13 \ \text{ or } \ x = -15\\\\

If x = 13, then x+2 = 13+2 = 15

Then note how x^2 + (x+2)^2 = 13^2 + 15^2 = 169 + 225 = 394

Or we could have x = -15 which leads to x+2 = -15+2 = -13

So, x^2 + (x+2)^2 = (-15)^2 + (-13)^2 = 225 + 169 = 394

We get the same thing either way.

<h3>Answer: Either 13, 15  or  -15, -13</h3>
4 0
3 years ago
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