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Oliga [24]
2 years ago
12

Could the following side lengths form a right triangle? Elplain 11,60,61

Mathematics
1 answer:
Bogdan [553]2 years ago
5 0

Answer:

Yes

Step-by-step explanation:

A^2+B^2=C^2

11^2+60^2=61^2

121+3600=3721

3721=3721

:)

You might be interested in
What type of number is 37.9? <br><br> A. Real <br> B . Imaginary <br> C. Complex
Yanka [14]

Answer:

A. Real number

Step-by-step explanation:

Fact :Real numbers that include decimal points are known as floating point numbers because the decimal floats within the numbers.

7 0
3 years ago
Amanda put $1500 in her savings account. After five years she had $1833 in the account. What rate of interest did she earned use
sveta [45]

Answer: 4.01% interest rate

This value is approximate. It is rounded to the nearest hundredth of a percent.

============================================

Work Shown:

A = P*e^(r*t)

1833 = 1500*e^(r*5)

1833/1500 = e^(5r)

1.222 = e^(5r)

e^(5r) = 1.222

5r = Ln(1.222)

5r = 0.2004888607494

r = 0.2004888607494/5

r = 0.04009777214989

r = 0.0401

r = 4.01%

4 0
3 years ago
Pls help me with this question i only get one try
DiKsa [7]
Answer: 144,000 typewriters

Step-by-step explanation:
Ok so, use the formula I= PRT.
Principal, rate, and time.

First, turn the % into 100..
Or just move the decimal two times to the right.
= 0.20

Next, Skip this. There is no next ‍♀

Finally, multiply. 120,000× 0.20 × 6
Giving you the answer of, 144,000 typewriters.

Hopefully this helps ‍♀
5 0
3 years ago
. An insurance company offer contracts for a certain peril. In a contract period, which is 6 months, the following payoffs can o
Damm [24]

Answer and Step-by-step explanation:

The answer is attached below

5 0
4 years ago
Exercise 3.3.2: Verify that the system x® 0 1 3 3 1 x® has the two solutions 1 1 e 4t and 1 −1 e −2t a) . b) Write down the gene
nikklg [1K]

Answer:

The general solution of the system is

X(t)=A\left(\begin{array}{c}1 &-1 \end{array}\right)e^{-2t} + B\left(\begin{array}{c}1 &1 \end{array}\right)e^{4t}\\

Step-by-step explanation:

To verify that the system X^{'} =\left[\begin{array}{cc}1&3\\3&1\end{array}\right] X has the solutions given,

First, we determine the Eigen Values β of the matrix of the form X^{'} =A XUsing |A-βI|=0, where I is the Identity Matrix, we have:

|A-\beta I|=0

|\left(\begin{array}{cc}1&3\\3&1\end{array}\right )-\left(\begin{array}{cc}\beta &0\\0&\beta \end{array}\right )|=0

Subtracting matrices

\left|\begin{array}{cc}1-\beta &3\\3&1-\beta \end{array}\right |=0

Taking the determinant

(1-\beta)(1-\beta)-(3X3)=0\\1-\beta-\beta+\beta^{2}-9=0\\\beta^{2}-2\beta-8=0\\\beta^{2}-4\beta+2\beta-8=0\\\beta(\beta-4)+2(\beta-4)=0\\(\beta-4)((\beta+2)=0\\\beta=4  or -2

We determine the eigen vector using\left(\begin{array}{cc}1-\beta &3\\3&1-\beta \end{array}\right)\left(\begin{array}{c}c_{11} &c_{12} \end{array}\right)=0

When \beta = -2,

\left(\begin{array}{cc}3 &3\\3&3 \end{array}\right)\left(\begin{array}{c}c_{11} &c_{12} \end{array}\right)=0 which implies that 3c_{11}+3c_{12}=0 and thus  

If c_{11}=1, c_{12}=-1

When \beta = 4,

\left(\begin{array}{cc}-3 &3\\3&-3 \end{array}\right)\left(\begin{array}{c}c_{21} &c_{22} \end{array}\right)=0 which implies that 3c_{21}-3c_{22}=0 and thus  

If c_{21}=1, c_{22}=1

A general solution of the system is given as

X(t)=Ac_{1}e^{\beta _{1}} + Bc_{2}e^{\beta _{2}t where the c's are the eigen vectors.

Thus the general solution is

X(t)=A\left(\begin{array}{c}1 &-1 \end{array}\right)e^{-2t} + B\left(\begin{array}{c}1 &1 \end{array}\right)e^{4t}\\

7 0
3 years ago
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