Answer: e. each component be identified by a coding scheme that specifies size, shape, and the type of processing.
Step-by-step explanation:
Group technology is a technique in manufacturing that involves bringing together parts with similar process of manufacturing or function into the same location so that they can all go through the same process. This follows a general saying that problems with similar groups could possibly be solved using a single or similar solution, which could help save time, resources and efforts.
Answer:
Step-by-step explanation:
K=2J-3
Complete Question
Evaluate the Fermi function for an energy kT above the Fermi energy. Find the temperature at which there is a 1% probability that a state, with an energy 0.5 eV above the Fermi energy, will be occupied by an electron.
Answer:
a
The Fermi function for the energy KT is 
b
The temperature is 
Step-by-step explanation:
From the question we are told that
The energy considered is 
Generally the Fermi function is mathematically represented as
![F(E_o) = \frac{1}{e^{\frac{[E_o - E_F]}{KT} } + 1 }](https://tex.z-dn.net/?f=F%28E_o%29%20%3D%20%20%5Cfrac%7B1%7D%7Be%5E%7B%5Cfrac%7B%5BE_o%20-%20E_F%5D%7D%7BKT%7D%20%7D%20%2B%201%20%7D)
Here K is the Boltzmann constant with value 
is the Fermi energy
is the initial energy level which is mathematically represented as

So
![F(E_o) = \frac{1}{e^{\frac{[[E_F + KT] - E_F]}{KT} } + 1}](https://tex.z-dn.net/?f=F%28E_o%29%20%3D%20%20%5Cfrac%7B1%7D%7Be%5E%7B%5Cfrac%7B%5B%5BE_F%20%2B%20KT%5D%20-%20E_F%5D%7D%7BKT%7D%20%7D%20%2B%201%7D)
=> 
=> 
=> 
Generally the probability that a state, with an energy 0.5 eV above the Fermi energy, will be occupied by an electron is mathematically represented by the Fermi function as
![F(E_k) = \frac{1}{e^{\frac{[E_k - E_F]}{KT_k} } + 1 } = 0.01](https://tex.z-dn.net/?f=F%28E_k%29%20%3D%20%20%5Cfrac%7B1%7D%7Be%5E%7B%5Cfrac%7B%5BE_k%20-%20E_F%5D%7D%7BKT_k%7D%20%7D%20%2B%201%20%7D%20%20%3D%200.01)
Here
is that energy level that is 0.5 ev above the Fermi energy 
=> ![F(E_k) = \frac{1}{e^{\frac{[[0.50 eV + E_F] - E_F]}{KT_k} } + 1 } = 0.01](https://tex.z-dn.net/?f=F%28E_k%29%20%3D%20%20%5Cfrac%7B1%7D%7Be%5E%7B%5Cfrac%7B%5B%5B0.50%20eV%20%2B%20E_F%5D%20-%20E_F%5D%7D%7BKT_k%7D%20%7D%20%2B%201%20%7D%20%20%3D%200.01)
=> ![\frac{1}{e^{\frac{0.50 eV ]}{KT_k} } + 1 } = 0.01](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Be%5E%7B%5Cfrac%7B0.50%20eV%20%5D%7D%7BKT_k%7D%20%7D%20%2B%201%20%7D%20%20%3D%200.01)
=> ![1 = 0.01 * e^{\frac{0.50 eV ]}{KT_k} } + 0.01](https://tex.z-dn.net/?f=1%20%3D%200.01%20%2A%20e%5E%7B%5Cfrac%7B0.50%20eV%20%5D%7D%7BKT_k%7D%20%7D%20%2B%200.01)
=> ![0.99 = 0.01 * e^{\frac{0.50 eV ]}{KT_k} }](https://tex.z-dn.net/?f=0.99%20%3D%200.01%20%2A%20e%5E%7B%5Cfrac%7B0.50%20eV%20%5D%7D%7BKT_k%7D%20%7D)
=> ![e^{\frac{0.50 eV ]}{KT_k} } = 99](https://tex.z-dn.net/?f=e%5E%7B%5Cfrac%7B0.50%20eV%20%5D%7D%7BKT_k%7D%20%7D%20%20%3D%2099)
Taking natural log of both sides
=> 
=> 
Note eV is electron volt and the equivalence in Joule is 
So

=> 
Answer:
it would be 4 because when you put them in number order you would find 4 in the middle of them
13 x 12 = 156 square inches