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2 years ago

Six - two times twelve plus five

Mathematics

1 answer:

fomenos2 years ago

6 0

Answer:

Ok, so the equation would be 6-2*12+5. The answer to that is -13.

Step-by-Step Explanation:

You would use PEMDAS. First, you multiply 2 and 12 and that's 24. Now your equation is 6-24+5. Then you subtract 6 and 24 and that's -18. Now your equation is -18+5, and the answer to that equation is -13. I hope this helps you!!

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What is an equation for the line that passes through (-2,-3) with a slope of -1/2?

Crazy boy [7]

Answer:

Step-by-step explanation:

To write the equation of a line use the point slope form of a line substituting m = -1/2 and the point (-2,-3).

$y -y_1 = m(x-x_1)\\y --3=-\frac{1}{2}(x--2)\\y+3 = -\frac{1}{2}(x+2)$

Convert to standard form by applying the distributive property and rearranging the terms.

$y + 3 = -\frac{1}{2}(x+2)\\y+3 = -\frac{1}{2}x -1\\2y + 6 = -x -2\\x+2y + 6 = -2\\x + 2y = -8$

The equation x +2y = -8 is the same equation as 4y + 2x = -16 just doubled----> 2x + 4y = -16

8 0

2 years ago

X3= one over eight what's the answer for that?

Black_prince [1.1K]

X^3 = 1/8
x^3 = (1/2)^3
x = 1/2

hope it helps

6 0

2 years ago

Simplify -5-√-44<br><br> i have no idea

Tatiana [17]

Answer:

Undefined

Step-by-step explanation:

The square root of a negative number does not exist in the set of real numbers so it would be Undefined

6 0

2 years ago

Simplyify t^12/t^6 *PLEASE HELP*

Julli [10]

Answer:

Step-by-step explanation:

In division when bases are same you do top exponent minus bottom exponent.

So here you do t^(12-6) which is t^6.

3 0

2 years ago

The total resistance in a circuit with two parallel resistors is 2 ohms and R1 is 6 ohms. Using the equation for R2, in terms of

ivanzaharov [21]

<h2>Answer:</h2>

$R_2$ is 3 ohms

<h2>Step-by-step explanation:</h2>

In a circuit containing two resistors $R_1$ and $R_2$ connected together in parallel, the total resistance $R_T$ is given by;

$\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2}$ ---------(i)

<em>Make </em> $R_2$ <em> subject of the formula;</em>

=> $\frac{1}{R_2} = \frac{1}{R_T} - \frac{1}{R_1}$

=> $\frac{1}{R_2} = \frac{R_1 - R_T}{R_TR_1}$

=> ${R_2} = \frac{R_TR_1}{R_1 - R_T}$ ---------------(ii)

From the question,

$R_1$ = 6Ω

$R_T$ = 2Ω

Substitute these values into equation (ii) as follows;

=> ${R_2} = \frac{2*6}{6 - 2}$

${R_2} = \frac{12}{4}$

$R_2$ = 3Ω

Therefore, the value of $R_2$ = 3 ohms or $R_2$ = 3Ω

3 0

2 years ago