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Fynjy0 [20]
3 years ago
11

Consider the vector space p2 of polynomials of degree at most 2. let t be the linear transformation given by t(p(x)) = p(x − 1)

+ p(x + 1). find the matrix of t with regard to the basis {1, x, x 2 }.
Mathematics
1 answer:
Goryan [66]3 years ago
6 0
Observe what happens to the basis components under the transformation T:

T(1)=1+1=2=2\cdot1+0\cdot x+0\cdot x^2
T(x)=(x-1)+(x+1)=2x=0\cdot1+2\cdot x+0\cdot x^2
T(x^2)=(x-1)^2+(x+1)^2=2x^2+2=2\cdot1+0\cdot x+2\cdot x^2

So we can represent T with the matrix

\mathbf T=\begin{bmatrix}2&0&2\\0&2&0\\0&0&2\end{bmatrix}

To check this answer: If we take an arbitrary polynomial \mathbf p\in\mathbb P_2, i.e. the vector

\mathbf p=\begin{bmatrix}c\\b\\a\end{bmatrix}

corresponding to the polynomial p(x)=c+bx+ax^2=c\cdot1+b\cdot x+a\cdot x^2, we get

\mathbf{Tp}=\begin{bmatrix}2a+2c\\2b\\2a\end{bmatrix}=(2a+2c)\cdot1+2b\cdot x+2a\cdot x^2

Substituting \mathbf p into the rule above, we get

p(x-1)+p(x+1)=a(x-1)^2+b(x-1)+c+a(x+1)^2+b(x+1)+c
p(x-1)+p(x+1)=(2a+2c)+2bx+2ax^2

as expected.
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Step-by-step explanation:

Assuming that 3 cm, 4 cm and 5 cm are the length of the sides of a triangle, then a right triangle is formed, in which 5 cm is the length of the hypotenuse and 3 cm and 4 cm are the length of the legs.

Angle A is either the angle between 4 cm and 5 cm sides or between 3 cm and 5 cm sides. For the first case:

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