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3 years ago

What is 1/8 times 5 1/2

Mathematics

2 answers:

sergiy2304 [10]3 years ago

8 0

Answer: 5 5/8

Hopefully this is correct

Hope this help if it didnt im so sorry :)

olganol [36]3 years ago

8 0

Answer:

$\frac{11}{16}$

Step-by-step explanation:

5 1/2 = 11/2

$\frac{1}{8}$ x $\frac{11}{2}$ = $\frac{11}{16}$

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3 years ago

___H2 + ___Br2 → ___HBr

Vaselesa [24]

Answer:H2+Br2-->2HBr

Step-by-step explanation:

The amount of atoms on the left side must be equal to the amount of atoms on the right side for each element.

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This means you must have the same amount on the right.

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4 years ago

3^x= 3*2^x solve this equation

kompoz [17]

In the equation

$3^x = 3\cdot 2^x$

divide both sides by $2^x$ to get

$\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3$

Take the base-3/2 logarithm of both sides:

$\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}$

Alternatively, you can divide both sides by $3^x$ :

$\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13$

Then take the base-2/3 logarith of both sides to get

$\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}$

(Both answers are equivalent)

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3 years ago

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