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3 years ago

What is 7.504-2.3792 rounded to the hundred

Mathematics

1 answer:

Liula [17]3 years ago

8 0

Answer:

Step-by-step explanation:

First what we have to do is subtract 7.504 and 2.3792
7.504 - 2.3792 = 5.1248
then what we do is
find the number in the number in the hundreds place 0 and look one place to the to the right for the rounding digit 0.
Round up if this number is greater than or equal to 5 and round down if less than five.

Since zero is less than five we would round down

so our answer is zero

Hope this helps

Hope u get it right

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What is the answer for 5.2 × 10-9 + 3.1 × 10-8 = × 10?

vlabodo [156]

Subtract x^10 from both sides. add 17 to both sides. divide both sides by 7.3 take root and the answer should be x=1.08821, -1.08821

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4 years ago

Write the equation of a circle with a center at (1, 4) where a point on the circle is (4, 8).

mina [271]

Notice the picture below

$\bf \textit{equation of a circle}\\\\
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad center\ ({{ h}},{{ k}})\qquad
radius={{ r}}\\\\
-----------------------------\\\\
\textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 1}}\quad ,&{{ 4}})\quad 
% (c,d)
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5 0

3 years ago

PLEASE HELP ASAP! Will give BRAINLIEST! Please answer correctly! No guessing!

Klio2033 [76]

Answer:

c.)

Step-by-step explanation:

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4 years ago

Read 2 more answers

A scuba diver is exploring at an elevation of -12.2 meters. As the diver rises to the surface, she plans to stop and rest briefl

svlad2 [7]

Answer:

7.65 meters.

Step-by-step explanation:

Let x represent the distance that diver will travel.

We have been given that a scuba diver is exploring at an elevation of -12.2 meters. As the diver rises to the surface, she plans to stop and rest briefly at a reef that has an elevation of -4.55 meters. We are asked to find the distance that diver will travel.

The initial elevation plus x will be equal to -4.55 meters. We can represent our given information in an equation as:

$-12.2+x=-4.55$

$-12.2+12.2+x=-4.55+12.2$

$x=7.65$

Therefore, the scuba diver will travel a vertical distance of 7.65 meters.

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3 years ago

A man walks along a straight path at a speed of 4 ft/s. A searchlight is located on the ground 20 ft from the path and is kept f

krek1111 [17]

Answer:

0.128rad/sec

Step-by-step explanation:

Let x represent the between the man and the point on the path

θ = the angle

dx/dt = 4 ft/s

dθ/dt = rate is the searchlight rotating when the man is 15 ft from the point on the path closest to the searchlight

tan θ = x/20 ft

Cross Multiply

20tan θ = x

dx/dt = 20sec² θ dθ/dt

dθ/dt = 1/20 × cos² θ dx/dt

dθ/dt= 1/20 × cos² θ × 4

dθ/dt = 1/5 × cos² θ

Note : cos θ = 4/5

dθ/dt = 1/5 × (4/5)²

dθ/dt = 16/125

dθ/dt = 0.128rad/sec

6 0

3 years ago