4x - 5y = -12
-x + 5y = 18
Add the equations together:
4x + -x = 3x
-5y + 5y = 0
-12 + 18 = 6
So now you have:
3x = 6
Divide both sides by 3:
X = 2
Now you have the value of x, replace x with 2 in one of the equations and solve for y:
4(2) -5y = -12
8 -5y = -12
Subtract 8 from both sides:
-5y = -20
Divide both sides by -5:
Y = 4
The solution is x = 2 and y = 4 which is written as (2,4)
Answer:
Step-by-step explanation:
From the given information:
The domain D of integration in polar coordinates can be represented by:
D = {(r,θ)| 0 ≤ r ≤ 6, 0 ≤ θ ≤ 2π) &;
The partial derivates for z = xy can be expressed as:

Thus, the area of the surface is as follows:





![= 2 \pi \times \dfrac{1}{3} \Bigg [ (37)^{3/2} - 1 \Bigg]](https://tex.z-dn.net/?f=%3D%202%20%5Cpi%20%5Ctimes%20%5Cdfrac%7B1%7D%7B3%7D%20%20%5CBigg%20%5B%20%2837%29%5E%7B3%2F2%7D%20-%201%20%5CBigg%5D)
![= \dfrac{2 \pi}{3} \Bigg [37 \sqrt{37} -1 \Bigg ]](https://tex.z-dn.net/?f=%3D%20%5Cdfrac%7B2%20%5Cpi%7D%7B3%7D%20%5CBigg%20%5B37%20%5Csqrt%7B37%7D%20-1%20%5CBigg%20%5D)
Answer:
42 cakes
Step-by-step explanation:
10+32=42 cakes
Graph images undergo transformations, one of the types of transformations are rotations.
rotation is done when each point of the image rotates 90° around a point in the counterclockwise manner.
when rotation is done, (x,y) -> (-y,x)
therefore when taking points from image to original then the reverse is done ;
(-y,x) --> (x,y)
the coordinates of image point q' is (-3,4)
before rotation then the coordinates are (4,3)
answer is (4,3)
Hi there
-5i + 5-1 + 6
= -5i + 11- 1
= 5i + 10
That's the answer :0
I hope that's help... Do you have any question ?