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Tema [17]
3 years ago
8

What is 7.504-2.3792 rounded to the hundred

Mathematics
1 answer:
Liula [17]3 years ago
8 0

Answer:

0

Step-by-step explanation:

  • <u><em>First what we have to do is subtract 7.504 and 2.3792 </em></u>
  • <u><em>7.504 - 2.3792 = 5.1248</em></u>
  • <u><em>then what we do is</em></u>
  • <u><em>find the number in the number in the hundreds place 0 and look one place to the to the right for the rounding digit 0. </em></u>
  • <u><em>Round up if this number is greater than or equal to 5 and round down if less than five.</em></u>

<u><em></em></u>

<u><em>Since zero is less than five we would round down</em></u>

<u><em>so our answer is zero</em></u>

<u><em></em></u>

<u><em>Hope this helps</em></u>

<u><em>Hope u get it right</em></u>

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The function below has at least one rational zero.
Dmitry_Shevchenko [17]

Answer:

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Step-by-step explanation:

<u>Factor by grouping</u>

g(x)=5x^4+38x^3+18x^2-22x-7\\\\g(x)=5x^4+33x^3-15x^2-7x+5x^3+33x^2-15x-7\\\\g(x)=x(5x^3+33x^2-15x-7)+1(5x^3+33x^2-15x-7)\\\\g(x)=(x+1)(5x^3+33x^2-15x-7)\\\\g(x)=(x+1)(5x^3+35x^2-2x^2-14x-x-7)\\\\g(x)=(x+1)(5x^2(x+7)-2x(x+7)-1(x+7))\\\\g(x)=(x+1)(x+7)(5x^2-2x-1)\\\\0=(x+1)(x+7)(5x^2-2x-1)\\

We can easily see that the first two zeroes are x=-1 and x=-7, however, the third zero will need the help of the quadratic formula:

0=5x^2-2x-1\\\\x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\ \\x=\frac{-(-2)\pm\sqrt{(-2)^2-4(5)(-1)}}{2(5)}\\\\x=\frac{2\pm\sqrt{4+20}}{10}\\ \\x=\frac{2\pm\sqrt{24}}{10}\\ \\x=\frac{2\pm2\sqrt{6}}{10}\\ \\x=\frac{2}{10}\pm\frac{2\sqrt{6}}{10}\\ \\x=\frac{1}{5}\pm\frac{\sqrt{6}}{5}\\\\x_1\approx0.689898\\\\x_2\approx-0.289898

Therefore, the zeroes of the function are x=-7,x=-1,x=-0.289898,x=0.689898

7 0
3 years ago
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