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Alexxandr [17]
3 years ago
14

sandy has 20 roses,5 daisies,and 10 tulips.She wants to arrange all the flowers in bouquets .Each bouquet has the same number of

flowers and the same type of flower.What is the greatest number of flowers that could be in a bouquet?
Mathematics
1 answer:
mixas84 [53]3 years ago
6 0

Answer:

The answer is: The greatest number she can have is 11.

Step-by-step explanation:

20 can be divided by 5, which makes 4. 5 can be divided by 5, which makes 1. 10 can be divided by 5, which makes 2. If you add your quotients (4, 5, and 2) then you will get your answer.

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Let u = <3, -1>, v = <-6, -6>. Find 9u + 2v.
Gnom [1K]
9u means you're multiplying 9 into that vector, both components.  Same with the 2v.  9*3 = 27 and 9*-1 = -9, so your new vector u is <27, -9>.  Now let's do v.  2* -6 (twice) = -12, so your new v vector is <-12, -12>.  Add those together now, first components of each and second components of each.  27 + (-12) = 15; -9+(-12)=-21.  So the addition of those gives us a final vector with a displacement of <15, -21>
5 0
3 years ago
What are the zeros of the polynomial function f(x) = x^3-10x^2+24x
Ludmilka [50]
Replace F(x) with y
y=x^3-10x^2+24x
To find the roots replace y with 0.
0=x^3-10x^2-24x
Rewrite the equation as
x^3-10x^2+24x=0
Factor the left side
x(x-6)(x-4)=0
The solution is a result of
x=0, x-6=0, and x-4=0

The answer is:
x=0, 6, 4
3 0
3 years ago
A team of three students are working on a language-learning app; they need to develop 300 micro-lessons and 300 micro-tests befo
Olegator [25]

Answer: a) 15 b)

Step-by-step explanation:

Let X be the number of days:

a)

For LESSONS:

Jordan does 10 / day ( 10*X)

Marco 5 / day ( 5*X)

Junyi 5 / day ( 5*X)

For TESTS:

Jordan does 5 / day ( 5*X)

Marco 10 / day ( 10*X)

Junyi 8 / day ( 8*X)

for each they need a total of 300

a) 10X+5X+5X=300 => 20X = 300 => X = 15 days for the lessons

b) 5X+10X+8X = 300 => 23X = 300 => X = 13.04 days for the tests

so they need 15 days to finish both tasks

now if Junyi gets sick we just eliminate his contribution

a) 10X+5X=300 => 15X = 300 => X = 20 days for the lessons

b) 5X+10X = 300 => 15X = 300 => X = 20 days for the tests

so in 20 days they will finish without him

If jordan works 10 hours a day, we just replace him with 10/24

a) 10(10/24)+5X+5X= 300 => X = 29.58 days for the lessons

b) 5(10/24)+10X+8X = 300 => X = 16.51 days for the tests

so at the end to complete both tasks they need 29.58 days

4 0
3 years ago
Find the equation who’s roots are (3,0) and (2-5i, 0)
Lana71 [14]
3,0 x 2-5i, 0 = ___ 9i
5 0
3 years ago
6 + (9 − 1) 2 ÷ 4 ⋅ 1 over 2 whole to the power of 4
Bas_tet [7]

Answer:

625

Step-by-step explanation:

1. parenthesis first, so it simplifies to ((6+(8)2÷4*1)/2)^4

2. pemdas says that multiplication and division go before addition and subtraction, so ((6+(8)2÷4*1)/2)^4 becomes ((6+16÷4*1)/2)^4 ---> ((6+4)/2)^4

3. then simplify inside of the parenthesis, so it becomes 5^4, which is 625

6 0
2 years ago
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