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netineya [11]
3 years ago
13

suppose that unit price p in dollars for a quantity demanded X of a certain product of a company is given by p=-0.08+620 (0 <

x <14,000). find the revenue function. marginal revenue function.
Mathematics
1 answer:
77julia77 [94]3 years ago
7 0
I am sorry, I would love to help but I am not sure. Good luck anyways. :(
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Use the circle graph to determine how much hours per day Becky spends on each activity?
blagie [28]

WE know 1 day = 24 hours

To find number of hours spent on each activity, we multiply the corresponding percentage by 24

School :         25 % --> 0.25 * 24 = 6.00 hrs

Eating :          10 % ----> 0.1 * 24 = 2.40 hrs

Sleep :           40 % ----> 0.4 * 24 = 9.60 hrs

Homework:   10 % ---->0.1 * 24 = 2.40 hrs

Free time:      15 % -----> 0.15 * 24 = 3.60 hrs



7 0
4 years ago
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DUE IN 2 minutes<br> pls help
iragen [17]

Answer: I can’t see the numbers dude.

Step-by-step explanation:

Sorry

4 0
3 years ago
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7=x+3. What is being done to the variable?
creativ13 [48]

Step-by-step explanation: If you take a look at the right side of the equation, a 3 is being added to our variable <em>x</em>.

If you were going to solve this equation, you must subtract 3 from the right side and the left side to isolate our variable.

You would end up with 4 = x.

3 0
3 years ago
Solve this problem. A florist sells holiday bouquets that use roses and carnations in a ratio of 2 to 7. She receives a shipment
DIA [1.3K]

Let roses be R and carnations be C

"in a ratio of 2 to 7" means that the ratio of R to C is 2 to 7, meaning you'll have to cross multiply to translate it algebraically

R:C\\2:7\\7R=2C\\

since C = 343 we plug 343 in 7R=2C:

7R=2(343)\\7R=686\\R=\frac{686}{7} \\R=98

ergo, she needs 98 roses

to make sure of the answer:

"ratio of 2 to 7" is technically a fraction =>  \frac{2}{7}

and since the ratio of the roses to the carnations is the same as \frac{2}{7} we plug the values R = 98 and C=343:

\frac{R}{C}=\frac{98}{343}=\frac{2}{7}

check with calculator too, hope i helped <33

6 0
3 years ago
49 points, will give Brainliest! Having a lot of trouble with Determining the domains of functions. Khan Academy Algebra I.
prohojiy [21]

Domains of functions are the values that <em>can</em> be plugged into the function and not "break" it. By "break" I mean that the denominator cannot be 0, in this case. If the denominator is 0, we will get a divide by 0 error, and thus, we must restrict the domain. All values of x will work except 9/4:

\frac{7-3x}{4x-9}

Let's plug in 9/4 and see what happens:

\frac{7-3(\frac{9}{4})}{4(\frac{9}{4})-9}   = \frac{whatever}{0}

So, plugging in 9/4 results in denominator equalling 0. Therefore, we must restrict the domain so that x ≠ 9/4. Your answer is All real values of x such that x ≠ 9/4.

6 0
4 years ago
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