3 years ago

Please help!

Mathematics

1 answer:

Mars2501 [29]3 years ago

7 0

4 4 10! Is the solution

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Y= x^2 -5 solve for x

dexar [7]

$Y= x^2 -5$

We need to solve for x, we need to get x alone

$Y= x^2 -5$

Lets start by removing -5

Add 5 on both sides

$y + 5= x^2 -5 + 5$

$y + 5= x^2$

Now to isolate x , we need to remove the square from x

To remove square , take square root on both sides

$+-\sqrt{y+5} = \sqrt{x^2}$

square and square root will get cancelled

$+-\sqrt{y+5} = x$

So $x = +\sqrt{y+5}$ and $x = -\sqrt{y+5}$

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aev [14]

Your answer is True !:)

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PLEASE HELP! <3<br> What is the slope of the line?

GrogVix [38]

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