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Kitty [74]
2 years ago
5

A mechanic has sockets with sizes shown below. Write each fraction in the correct box.​

Mathematics
1 answer:
notsponge [240]2 years ago
5 0

Missing Details:

Write each fraction in the correct box.

1/8in, 5/8in, 8/16in, 9/16in, 15/16in, 5/6in

Less than: 1/2inch,

Equal to: 1/2inch

Greater than: 1/2inch

Answer:

Less than: 1/2inch---> 1/8 in

Equal to: 1/2inch ---> 8/16 in

Greater than: 1/2inch ---> 5/8in, 9/16in, 15/16in, 5/6in

Step-by-step explanation:

Given

Sizes: 1/8in, 5/8in, 8/16in, 9/16in, 15/16in, 5/6in

Required

Match the size with the correct inequalities

Convert 1/2in to decimal

\frac{1}{2}\ in = 0.5\ in

Next, we convert each size to decimal and compare the decimal equivalent to 0.5in

Convert 1/8in to decimal

\frac{1}{8}\ in = 0.125\ in

<em>0.125 is less than 0.5in</em>

Convert 5/8in to decimal

\frac{5}{8}\ in = 0.625\ in

<em>0.625 is greater than 0.5in</em>

Convert 8/16in to decimal

\frac{8}{16}\ in = 0.5\ in

<em>0.5 is equal to 0.5in</em>

Convert 9/16in to decimal

\frac{9}{16}\ in = 0.5625\ in

<em>0.5625 is greater than 0.5in</em>

Convert 15/16in to decimal

\frac{15}{16}\ in = 0.9375\ in

<em>0.9375 is greater than 0.5in</em>

Convert 5/6in to decimal

\frac{5}{6}\ in = 0.833\ in

<em>0.833 is greater than 0.5in</em>

So, we have:

<em>Less than: 1/2inch---> 1/8 in</em>

<em>Equal to: 1/2inch ---> 8/16 in</em>

<em>Greater than: 1/2inch ---> 5/8in, 9/16in, 15/16in, 5/6in</em>

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Now, you're looking for \delta>0 such that for any \varepsilon>0, you have

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Deon has a pizza with a diameter
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The square box is enough to fit the pizza with a diameter of 10 inches inside. Since the area of the square box is more than the area of the pizza, the pizza fits easily in the square box.

<h3>What is the area of the circle and the square?</h3>

The area of the circle is

Ac = πr² = πd²/4 sq. units

Where r is the radius and d is the diameter of the circle.

The area of the square is given by

As = s² sq. units

Where s is the length of the side of a square.

<h3>Calculation:</h3>

It is given that a pizza(in a circular shape) with a diameter d = 10 in is to be placed in a square box of the same length as the diameter of the pizza.

So,

The area of pizza is

Ap = Ac = πd²/4 sq. units

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Then, the area of the square box with the length same as the diameter of the pizza is,

As = d²

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Since the area of the square is more than the area of the pizza (100 sq. inch > 78.54 sq. inch), the pizza easily fits into the square box.

Learn more about the area of a circle here:

brainly.com/question/15673093

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3m - 5n + 6m - 8n \\ 3m + 6m - 5n - 8n \\ 9 m- 13n

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