Since <span> sin(α) > 0 and cos(α) > 0
so </span><span>α is IN THE FIRST QUADRANT (I)</span>
Answer: 10 ornaments
Step-by-step explanation:
From the question, we are informed that students are making ornaments and each takes 1/4 of a piece of Bristol board. We are further told that they go to the cupboard and find 2 1/2 pieces of Bristol board.
The number of ornaments that they make will be gotten by dividing 2 1/2 by 1/4. This will be:
= 2 1/2 ÷ 1/4
= 5/2 ÷ 1/4
= 5/2 × 4/1
= 10
They can make 10 ornaments
I think it may be: 0.66666666666
I only looked it up on the internet.
2y + x = 4
x = -2y + 4
y = x^2 - 6x + 8
y = (-2y + 4)^2 - 6(-2y + 4) + 8
y = (-2y + 4)(-2y + 4) + 12y - 24 + 8
y = 4y^2 - 8y - 8y + 16 + 12y - 24 + 8
y = 4y^2 - 4y
4y^2 - 4y - y = 0
4y^2 - 5y = 0
y(4y - 5) = 0
y = 0 x = -2y + 4
x = -2(0) + 4
x = 4
4y - 5 = 0 x = -2y + 4
4y = 5 x = -2(5/4) + 4
y = 5/4 x = -10/4 + 4
x = -10/4 + 16/4
x = 6/4 which reduces to 3/2
so u have 2 sets of points that will work....
(4,0) and (3/2,5/4) <===
First step is to order the data from least to greatest.
10.5 11 11.5. 14.5 14.5 17 17 18 19
The median (Q2) is the middle number 14.5, this separates the lower half from the upper half. Q1 is the middle of the lower half, since there are an even amount of data, you have to take the average of the two middle numbers, 11 & 11.5, that would be 11.25; now we have to do the same with the upper half to find Q3, the average between 17 & 18 is 17.5
Now to find the IQR, subtract Q3 - Q1,
17.5 - 11.25 = 6.25
IQR = 6.25
