Question

Find the equation line of L in the forrm of y=mx+c

Answer 1

Answer:

Slope-intercept form of equation of line is, y = mx + c

Equation of line L is,  y = 5x - 5

From given figure, it is observed that line L is passing through point (0, -5) and (1, 0).

First we have to find slope (m) of line.

                     

So, equation of line becomes,

                         

Since, line passing through (1, 0). Therefore, substituting point (1, 0) in above equation of line.

We get,     c = - 5

Thus, equation of line is,  

Step-by-step explanation:

Slope-intercept form of equation of line is, y = mx + c

Equation of line L is,  y = 5x - 5

From given figure, it is observed that line L is passing through point (0, -5) and (1, 0).

First we have to find slope (m) of line.

                     

So, equation of line becomes,

                         

Since, line passing through (1, 0). Therefore, substituting point (1, 0) in above equation of line.

We get,     c = - 5

Thus, equation of line is,  

Answer 2

Answer:

y = $\frac{5}{2}$ x + 10

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- 4, 0) and (x₂, y₂ ) = (0, 10) ← 2 points on the line

m = $\frac{10-0}{0-(-4)}$ = $\frac{10}{0+4}$ = $\frac{10}{4}$ = $\frac{5}{2}$

the line crosses the y- axis at (0, 10 ) ⇒ c = 10

y = $\frac{5}{2}$ x + 10 ← equation of line