Let us bear in mind the equivalent value of these coins:
One dime = $0.10
One quarter = $0.25
Let x = number of dimes
y<span> = number of quarters</span>
Since the boy has 70 coins in total, we can say that:
<span>x + y = </span><span>70 </span>(can be written as x = 70 – y)
Since the boy has a total of $12.40, we can say that:
0.10x + 0.25y = 12.40
To solve this problem, we need to solve this system of equation. We have to substitute the value of x as written in the first equation (x = 70 –y)
0.10(70 – y) + 0.25y = 12.40
7 – 0.10y + 0.25y = 12.40
0.15y = 5.40
y = 36
X = 70 – 36
X = 34
Therefore,<span> the boys </span>has<span> 34 dimes and 36 quarters. To check our answer, we just have to check if his money would total $12.40.</span>
34 dimes = $3.40
36 dimes = $9.00
<span>Total </span><span>$12.40</span>
The equation of nth term will be written as for n as will be (
- a₁ + d) / d. Then the correct option is D.
The missing options are attached to the picture given below.
<h3>What is a sequence?</h3>
A sequence is a list of elements that have been ordered in a sequential manner, such that members come either before or after.
The formula for the nth term of an arithmetic sequence can be found using the formula given below.

Then arrange the equation for n, we have

Then the correct option is D.
More about the sequence link is given below.
brainly.com/question/21961097
#SPJ1
Answer:
20160 pounds
Step-by-step explanation:
20 * 15 * 12 = 3600 feet^3 = Volume
3600 feet^3 * 5.6 pounds = 20160 lbs
Answer:
The probability that if a person is chosen at random has run to red light in the last year is 60%.
Step-by-step explanation:
Since a group of people were asked if they had run a red light in the last year, and 456 responded "yes", and 304 responded "no", to find the probability that if a person is chosen at random, they have run a red light in the last year, the following calculation must be performed:
456 + 304 = 760
760 = 100
456 = X
456 x 100/760 = X
45600/760 = X
60 = X
Therefore, the probability that if a person is chosen at random has run to red light in the last year is 60%.