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Feliz [49]
1 year ago
14

Use the information below to find RV.​

Mathematics
1 answer:
Inessa [10]1 year ago
5 0

Answer:

I think Rv = 37x but if you think not then Go with You're answer

Step-by-step explanation:

goodluck! :)

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How to simplify 2mg x 5m²k​
Damm [24]

hey, I'm not sure about this answer, but I think it's true, sorry

m(2g+5mk)

6 0
2 years ago
How many miles and feet are in 70,000 feet
puteri [66]
1 mile= 5280ft 70 000/ 5280= 13.33 Therefore, in 70000 feet, there is 13.33 miles. Hope this helps :)
4 0
2 years ago
2.54rounded to nearest tenth
Svetradugi [14.3K]
2.5 Is the answer. It is rounded to the nearest tenth.
6 0
3 years ago
Read 2 more answers
Mr. Mole left his burrow and started digging his way down at a constant rate. Time (minutes) Altitude (meters) 666 -20.4−20.4min
Juli2301 [7.4K]

Answer:

-6 meters.

Step-by-step explanation:

We have been given Mr. Mole left his burrow and started digging his way down at a constant rate.

We are also given a table of data as:

Time (minutes)     Altitude (meters)

6                                   -20.4

9                                   -27.6

12                                   -34.8

First of all, we will find Mr. Mole's digging rate using slope formula and given information as:

m=\frac{y_2-y_1}{x_2-x_1}, where,

y_2-y_1 represents difference of two y-coordinates,

x_2-x_1 represents difference of two corresponding x-coordinates of y-coordinates.

Let (6,-20.4) be (x_1,y_1) and (9,-27.6) be (x_2,y_2).

m=\frac{-27.6-(-20.4)}{9-6}

m=\frac{-27.6+20.4}{3}

m=\frac{-7.2}{3}

m=-2.4

Now, we will use slope-intercept form of equation to find altitude of Mr. Mole's burrow.

y=mx+b, where,

m = Slope,

b = The initial value or the y-intercept.

Upon substituting m=-2.4 and coordinates of point (6,-20.4), we will get:

-20.4=-2.4(6)+b

-20.4=-14.4+b

-20.4+14.4=-14.4+14.4+b

-6=b

Since in our given case y-intercept represents the altitude of Mr. Mole's burrow, therefore, the altitude of Mr. Mole's burrow is -6 meters.

6 0
2 years ago
Read 2 more answers
the vertex of this parabola is at (3,5). When the y-value is 6, the x-value is -1. What is the coefficient of the squared term i
otez555 [7]
Now, assuming is a vertical parabola, so the squared variable is the "x", let's do some checking.

\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
vertex
\begin{cases}
h=3\\
k=5
\end{cases}\implies y=a(x-3)^2+5
\\\\\\
\textit{we also know that }
\begin{cases}
y=6\\
x=-1
\end{cases}\implies 6=a(-1-3)^2+5
\\\\\\
1=a(-4)^2\implies 1=16a\implies \cfrac{1}{16}=a
6 0
3 years ago
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