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Feliz [49]
2 years ago
14

Use the information below to find RV.​

Mathematics
1 answer:
Inessa [10]2 years ago
5 0

Answer:

I think Rv = 37x but if you think not then Go with You're answer

Step-by-step explanation:

goodluck! :)

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(−6)∙(a+2b−3c−4d)−(−2)∙(−4a−3b+2c+d)<br> please simplify asap
astraxan [27]
-6a-12b+18c+24d-8a-3b+4c+2d=-6a-8a-12b-3b+18c+4c+24d+2d=
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5 0
3 years ago
write an equation in standard form with integer coefficients for the line with slope 6/11 going through the point (-1,-6)
yKpoI14uk [10]
If the slope is 6/11 then, in y=mx+b form, m will be 6/11.  When you multiply 6/11 and -1 you get -6/11.  To get the y (-6), you have to add -60/11.  So in, y=mx+b form the equation is y=6/11x+(-60/11).  To make it standard form, you add negative 6/11x to both sides and then multiply by 11 to get rid of the fractions. So therefore the equation would be:

-6x + 11y = - 60
4 0
4 years ago
At the start of January, you have a credit card with a balance of $498, a credit limit of $900, and an interest rate of 15%. You
Vedmedyk [2.9K]
At the end of the January the balance of credit card need to be $498+$35=$533
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3 0
3 years ago
Need help fast please
dalvyx [7]

Answer:

13. The slope for a line that is perpendicular to the line y=4x+8 is  -1/4

14. The slope for a line that is perpendicular to the line x=-6 is 0

15. The equation for a line that is perpendicular to the line 8x-4y=12 and passes through the origin is y = - (1/2) x

16. The equation for a line that is perpendicular to the line y=-(1/3)x and passes through the point (0,-10) is y=3x-10

Step-by-step explanation:

13. What is the slope for a line that is perpendicular to the line y=4x+8?

y=mx+b

Comparing with the form slope-intercept, the slope of the given line is the coefficient of x, then the slope of the given line is 4.

A line perpendicular to y=4x+8 must have a slope opposite and inverse, then:

Slope of the perpendicular = - 1/4


14. What is the slope for a line that is perpendicular to the line x=-6?

The line x=-6 is a vertical line. A line perpendicular to the line x=-6 must be a horizontal line (Angle=0°), then:

Slope of the perpendicular = tan Angle = tan 0° = 0


15. Write the equation for a line that is perpendicular to the line 8x-4y=12 and passes through the origin.

8x-4y=12

Isolating y: Subtracting 8x both sides of the equation:

8x-4y-8x=12-8x

-4y=-8x+12

Dividing all the terms by -4:

-4y/(-4)= -8x/(-4)+12/(-4)

y=2x-3

The slope of the given line is 2

The slope of the perpendicular is m=-1/2 (opposite and inverse to the slope of the given line)

The perpendicular passes through the origin:

P1=(0,0)=(x1,y1)→x1=0, y1=0

Using the equation point - slope:

y-y1=m(x-x1)

Replacing the known values:

y-0=(-1/2)(x-0)

y=(-1/2)x


16. Write an equation for a line that is perpendicular to the line y=-(1/3)x and passes through the point (0,-10).

The slope of the given line is -(1/3)

The slope of the perpendicular is m=3/1→m=3 (opposite and inverse to the slope of the given line)

The perpendicular passes through the point:

P1=(0,-10)=(x1,y1)→x1=0, y1=-10

Using the equation point - slope:

y-y1=m(x-x1)

Replacing the known values:

y-(-10)=3(x-0)

y+10=3x

Isolating y: Subtracting 10 both sides of the equation:

y+10-10=3x-10

y=3x-10


 

8 0
4 years ago
273+147+325 how much is it all together
spin [16.1K]

Answer:

745

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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