4 years ago

The possible values of x are given by x−3≥2 . What is the least possible value of 5x ?

2 answers:

8 0

X has to be higher than 1. 5-3 is 2, which is equal to two but not greater than. X cannot be less than 1. To show this in an inequality:

x $\geq$ 1

Zigmanuir [339]4 years ago

3 0

$x-3\geq2 implies x \geq 3+2
hence x \geq 5$ .

this means x has smallest value 5.

THE SMALLEST VALUE OF 5X will thus be 5 * 5 = 25

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2 years ago

If r(X)=2-x^2 and w(X)=X-2, what is the range of (w*r)(X)

slega [8]

The given function are
r(x) = 2 - x² and w(x) = x - 2
(w*r)(x) can be obtained by multiplying the both function together

So, (w*r)(x) = w(x) * r(x) = (x-2)*(2-x²)
(w*r)(x) = x (2-x²) - 2(2-x²)
= 2x - x³ - 4 + 2x²

∴ (w*r)(x) = -x³ + 2x² + 2x - 4


It is a polynomial function with a domain equal to R

The range of (w*r)(x) can be obtained by graphing the function

To graph (w*r)(x), we need to make a table between x and (w*r)(x)

See the attached figure which represents the table and the graph of (w*r)(x)


As shown in the graph the range of (w*r)(x) is (-∞,∞)