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slava [35]
3 years ago
6

A jar contains nickles and pennies. There are 56 coins in the jar in all. The total value the total value of the coins are $1.52

. How many nickles ?
Mathematics
2 answers:
FrozenT [24]3 years ago
7 0
I would say there are at lest 1.00 of nickels someone check it i may be wrong.
timofeeve [1]3 years ago
6 0
<span>Let the number of nickles be x Let the number of pennies be y Value Value Type Number of of of of EACH ALL coin coins coin coins ------------------------------------------- nickles x $0.05 $0.05x pennies y $0.01 $0.01y ------------------------------------------- TOTALS 56 ----- $1.52 The first equation comes from the second column.</span>
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After traveling 345 miles, the
vfiekz [6]
<h2>GOOD LUCK CHUCK :)))))))))</h2>
5 0
3 years ago
Rectangle ABCD has vertices at (-7,-2); (1, -2); (1, -8); and (-7, -8) respectively. If GHJK is a similar rectangle where G(2, 5
Gennadij [26K]

Answer:

Points J and K could be located at:

J(2,2)

K(6,2)

Step-by-step explanation:

Consider the vertices have a x and y coordinate:

A: x coordinate=-7  y coordinate=-2

B: x coordinate=1  y coordinate=-2

C: x coordinate=1  y coordinate=-8

D: x coordinate=-7  y coordinate=-8

G: x coordinate=2  y coordinate=5

H: x coordinate=6  y coordinate=5

Then it is possible to calculate the distance between the x and y coordinates:

x coordinate of Vertices AB:

x coordinate of B- x coordinate of A=1-(-7)=8

The distance between A and B is 8

y coordinate of Vertices AC:

y coordinate of A- y coordinate of C=-2-(-8)=6

The distance between A and C is 6

Then we know that the side AB of Rectangle ABCD measures 8 and the side AC, measures 6.

Repeat the analysis  with Rectangle GHJK. In this case, is only possible to calculate the distance with x coordinate.

x coordinate of Vertices GH:

x coordinate of H- x coordinate of G=6-(2)=4

The distance between G and H is 4

We can see that the distance in x of the Rectangle ABCD is 8, and the distance in x of the Rectangle GHJK is 4, it means that <em>the measure of ABCD is twice GHJK.</em>

Then, if the distance in y coordinate of Vertices AC is 6, we could say that the distance in<em> y coordinate of Vertices GJ is 3.</em>

<em />

Points J and K could be located at:

J(2,2)

K(6,2)

3 0
3 years ago
The area of a rectangle is 4w - 10 square units.
podryga [215]

Area of rectangle = 2(2w - 5) is the factored form of given expression

Multiplying the length and width of a rectangle, we get the area of the rectangle

<em><u>Solution:</u></em>

Given that, area of rectangle is 4w - 10 square units

We have to factor the expression

From given,

Area of rectangle = 4w - 10

Take 2 as common factor

Area of rectangle = 2(2w - 5)

Thus the given expression is factored

<em><u>The area of rectangle is given as:</u></em>

Area\ of\ rectangle = length \times width

Area\ of\ rectangle = 2 \times (2w - 5)

Thus, multiplying the length and width of a rectangle, we get the area of the rectangle

When we multiply 2 with 2w - 5 we get the area of rectangle

From above we can say,

Length = 2 or 2w - 5

Width = 2w - 5 or 2

So when dimensions of rectangle are multiplied we get area of rectangle

3 0
2 years ago
A rectangular garden has side lengths of 12 feet and (x+10) feet. The garden has an area of 480 square feet. Write an equation a
Eddi Din [679]

Answer:

Step-by-step explanation:

12+x+10=480

22+x=480

x=458

2(12)+2(x+10)=480

24+2x+20=480

44+2x=480

2x=436

x=218

7 0
2 years ago
How do you do function machines?
timurjin [86]
Well you are going to need a rule or formula like x + 6 or 3 (x) + 2

Example:

Input x + 6 Output
2 2+ 6 8
4 4+6 10
6 6+6 12


Hope this helps sorry if it doesn’t
7 0
3 years ago
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