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Nat2105 [25]
2 years ago
11

Choose the best deciaml to represent 3 5/9

Mathematics
1 answer:
tamaranim1 [39]2 years ago
3 0

Answer:

A

Step-by-step explanation:

3x9 = 27

27+5 = 32

32/9 = 3.5 (w/dash above head)

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What is the result when the number 48 is decreased by 89%?
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Answer:

42.72

Step-by-step explanation:

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Teacher raises A school system employs teachers at
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By adding a constant value to every salary amount, the measures of

central tendency are increased by the amount, while the measures of

dispersion, remains the same

The correct responses are;

(a) <u>The shape of the data remains the same</u>

(b) <u>The mean and median are increased by $1,000</u>

(c) <u>The standard deviation and interquartile range remain the same</u>

Reasons:

The given parameters are;

Present teachers salary = Between $38,000 and $70,000

Amount of raise given to every teacher = $1,000

Required:

Effect of the raise on the following characteristics of the data

(a) Effect on the shape of distribution

The outline shape of the distribution will the same but higher by $1,000

(b) The mean of the data is given as follows;

\overline x = \dfrac{\sum (f_i \cdot x_i)}{\sum f_i}

Therefore, following an increase of $1,000, we have;

 \overline x_{New} = \dfrac{\sum (f_i \cdot (x_i + 1000))}{\sum f_i} =  \dfrac{\sum (f_i \cdot x_i + f_i \cdot 1000))}{\sum f_i} = \dfrac{\sum (f_i \cdot x_i)}{\sum f_i} + \dfrac{\sum (f_i \cdot 1000)}{\sum f_i}

\overline x_{New} = \dfrac{\sum (f_i \cdot x_i)}{\sum f_i} + \dfrac{\sum (f_i \cdot 1000)}{\sum f_i} = \dfrac{\sum (f_i \cdot x_i)}{\sum f_i} + 1000 = \overline x + 1000

  • Therefore, the new mean, is equal to the initial mean increased by 1,000

Median;

Given that all salaries, x_i, are increased by $1,000, the median salary, x_{med}, is also increased by $1,000

Therefore;

  • The correct response is that the median is increased by $1,000

(c) The standard deviation, σ, is given by \sigma =\sqrt{\dfrac{\sum \left (x_i-\overline x  \right )^{2} }{n}};

Where;

n = The number of teaches;

Given that, we have both a salary, x_i, and the mean, \overline x, increased by $1,000, we can write;

\sigma_{new} =\sqrt{\dfrac{\sum \left ((x_i + 1000) -(\overline x  + 1000)\right )^{2} }{n}} = \sqrt{\dfrac{\sum \left (x_i + 1000 -\overline x  - 1000\right )^{2} }{n}}

\sigma_{new} = \sqrt{\dfrac{\sum \left (x_i + 1000 -\overline x  - 1000\right )^{2} }{n}} = \sqrt{\dfrac{\sum \left (x_i + 1000 - 1000 - \overline x\right )^{2} }{n}}

\sigma_{new} = \sqrt{\dfrac{\sum \left (x_i + 1000 - 1000 - \overline x\right )^{2} }{n}} =\sqrt{\dfrac{\sum \left (x_i-\overline x  \right )^{2} }{n}} = \sigma

Therefore;

\sigma_{new} = \sigma; <u>The standard deviation stays the same</u>

Interquartile range;

The interquartile range, IQR = Q₃ - Q₁

New interquartile range, IQR_{new} = (Q₃ + 1000) - (Q₁ + 1000) = Q₃ - Q₁ = IQR

Therefore;

  • <u>The interquartile range stays the same</u>

Learn more here:

brainly.com/question/9995782

6 0
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Dmitrij [34]

Answer: The  below figure shows the graph of the given situation.

Step-by-step explanation:

Since, at first Caroline has brownies= 48

And, according to the question, it is decreasing by 6 per hour.

Then, the function of the given situation can be written as,

f(x)=48 - 6 x,     ------ (1)

where,  x is the number of hours and f(x) is the number of brownies Caroline has left in x hour.

Thus by substitution x= 0,1,2,3,4,5,6,7,8 in equation (1),

We get, f(x)=48, 42, 36, 30, 24, 18, 12, 6, 0

So, the function has points, (0, 48), (1, 42), (2, 36), (3, 30), (4, 24), (5,18 ),(6,12 ) (7, 6) (8, 0).

With help of the above points we can draw the graph of the given situation.

Note: since at x=8, f(x)=0 therefore after 8 hours she has no brownies left.


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